将带有数组的JSON文件转换为Java对象

Question

如何使用许多Arraysinside转换表单JSON？ 那怎么看我的JSON的一部分：    

private Double coordinateY;
private Double coordinateX;
private String nameStop;
private String withLine; ("headsigns" in JSON)

我的数据是带有对象停止的数据，带坐标，名称为Stop，以及总线（在JSON中是“标题”）：

@Autowired
JSON json;
@Autowired
Stop stop;

JSONParser parser = new JSONParser();
List<String> coordinates;
List<Stop> allStopList = new ArrayList<>();

public List<Stop> convert() {
    try {

        Object obj = parser
                .parse(new BufferedReader(new InputStreamReader(getClass().getResourceAsStream("poznanS.json"))));
        JSONObject jsonObject = (JSONObject) obj;
        JSONArray stopArray = (JSONArray) jsonObject.get("features");
        for (Iterator stopIndex = stopArray.iterator(); stopIndex.hasNext();) {
            JSONObject stopJSONObject = (JSONObject) stopIndex.next();
            JSONArray coordynateArray = (JSONArray) stopJSONObject.get("geometry");
            stop.setCoordinateY...
            stop.setCoordinateX...
            stop.setNameStop...
            stop.setWithLine...
        }

我的课我看起来像那样：

{
    "test": {
        "parts": [
             {
                "partgroup": "1",
                "screens": [
                    {
                        "questions": [
                            {
                                "questionno": 1
                            }
                        ]
                    }
                ]
            }
        ]
    }
}

Answer 1

使用javax.ws.rs.core.GenericType

例如：

protected List<TypeList> getTypesOfGroup(String group) {
            WebTarget target = restClient.getWebTargetByPath("typelist/groups").path(group);
            List<TypeList> types = target.request(RestClient.APPLICATION_JSON)
                    .get(new GenericType<List<TypeList>>() {
                    });
            return types;
        }