MySQL中的加权平均值计算？

Question

我目前正在使用以下查询来获取一些数字：

SELECT gid, count(gid), (SELECT cou FROM size WHERE gid = infor.gid)       
FROM infor 
WHERE id==4325 
GROUP BY gid;

我目前阶段的输出如下：

+----------+-----------------+---------------------------------------------------------------+
| gid      | count(gid)      | (SELECT gid FROM size WHERE gid=infor.gid)                    |
+----------+-----------------+---------------------------------------------------------------+
|       19 |               1 |                                                            19 | 
|       27 |               4 |                                                            27 | 
|      556 |               1 |                                                           556 | 
+----------+-----------------+---------------------------------------------------------------+

我试图计算加权平均值，即

  

（1 * 19 + 4 * 27 + 1 * 556）/（19 + 27 + 556）

有没有办法使用单个查询执行此操作？

Answer 1

使用：

SELECT SUM(x.num * x.gid) / SUM(x.cou)
  FROM (SELECT i.gid,
               COUNT(i.gid) AS num,
               s.cou
          FROM infor i
     LEFT JOIN SIZE s ON s.gid = i.gid
         WHERE i.id = 4325
      GROUP BY i.gid) x

Answer 2

您可以将原始查询作为子查询放置并对记录进行SUM整理。我无法测试这个，因为我没有你做的数据集，但它应该在理论上工作;）

SELECT SUM(gid)/SUM(weights) AS calculated_average FROM (
  SELECT gid, (COUNT(gid) * gid) AS weights
  FROM infor 
  WHERE id = 4325 
  GROUP BY gid);