Question

我有一个复选框，每次复选框的状态（选中/取消选中）时都会发送一个AJAX请求。我正在测试Chrome中的所有内容，一切正常。

但是，当我使用Firefox或IE时，AJAX请求不会更改SQL Server中的值。我有点困惑为什么它不起作用，而且我对JS和JQuery相当新，所以任何帮助都会非常感激。

这是我使用AJAX调用PHP页面来更改复选框值的函数。

        //This function handles the clicking of checkboxes in the list
        //It sends an ajax POST message to a separate php file that handles the database updating
        function checkboxClicked(checkboxType, ticketNumber){
            $.ajax({
                type: "POST",
                url: 'updateCheckbox.php',
                dataType: 'json',
                async: 'true',
                data: {checkboxType: checkboxType, ticketNumber: ticketNumber},

                success: function(result, status){
                    if (status == "success"){
                        console.log("Status: " + status + ", Result: " + result);
                    }
                }
            });

            if(checkboxType == "Received"){
                window.location.reload();
            }
        }

以下是PHP中显示复选框状态的行：

<?php
                        //This loop populates the ticket display using the records in the database
                        while($recordSet->EOF == false){
                            $ticketNumber = $recordSet->Fields['TicketNumber'];
                            $dateSubmitted = $recordSet->Fields['DateSubmitted'];
                            $department = $recordSet->Fields['Department'];
                            $courseNo = $recordSet->Fields['CourseNumber'];
                            $instructorName = $recordSet->Fields['InstructorName'];
                            $received = ($recordSet->Fields['Received']) ? "checked" : "unchecked";
                            $sendReminder = ($recordSet->Fields['SendReminder']) ? "checked" : "unchecked";
                            $email = $recordSet->Fields['Email'];
                            $CC = $recordSet->Fields['CC'];


                            $strHTML  = "<tr><td>$dateSubmitted</td>\n";
                            $strHTML .= "<td>$department</td>\n";
                            $strHTML .= "<td>$courseNo</td>\n";
                            $strHTML .= "<td style='word-break: break-all'>$instructorName</td>\n";
                            $strHTML .= "<td align='center'> <input type='checkbox' id='received' ".$received." class='receivedCheckbox' onclick='checkboxClicked(\"Received\", ".$ticketNumber.")'/></td>\n";
                            $strHTML .= "<td align='center'> <input type='checkbox' id='sendReminder' ".$sendReminder." class='sendReminderCheckbox' onchange='checkboxClicked(\"SendReminder\", ".$ticketNumber.")' data-email='".$email."'/></td>\n";
                            $strHTML .= "<td style='word-break: break-all;' align='center'> <a id='checkReceived' href='#' onClick='checkReceived(\"$received\", \"$email\")'>".$email."</a></td>";
                            $strHTML .= "<td align='center'> <button onclick=\"window.open('urlhere', '_self')\">Edit</button>\n";
                            $strHTML .= "<td align='center'> <button onclick=\"window.open('urlhere')\">Print</button> </td>\n";
                            $strHTML .= "</tr>\n";

                            echo $strHTML;
                            $recordSet->MoveNext;
                        }
                    ?>

如果您需要更多信息，请告诉我们。谢谢！

Answer 1

可能你应该尝试：

 $received = ($recordSet->Fields['Received']) ? "checked='checked' " : "checked='' ";
 $sendReminder = ($recordSet->Fields['SendReminder']) ? "checked='checked' " : "checked='' ";

Firefox和IE的AJAX请求问题

1 个答案: