Question

我使用php和javascript构建了一个在chrome中运行良好的Web表单。但是从IE或Firefox查看时。所有数据都在最终页面上正确显示，但实际上没有任何内容提交到我的数据库（MySQL / phpmyadmin）。这些提交在chrome上正常工作。当使用最新版本的phpmyadmin和mysql对更高版本的apache进行测试时没有问题。我如何解决apach2.2和mysql 5.5.42以解决这个问题...

<?php
$premC;
$NoR;
$CC;
$SD;
$HD;
$pack1;
$pack2;
$pack3;
$equipC;
$roomC;
$totalC;
$fname;
$lname;
$emailV;
$_SESSION['rebate'] = $_POST['rebate'];
$connect = mysqli_connect('localhost','*****','*****','*****');
  if(!$connect){
        die('Could not Connect: ' . mysqli_error($connect));
    }
$stmt = $connect->prepare("INSERT INTO form_test (Number_of_Rooms,Current_Monthly_Cost,SD,HD,Family,Entertainment,Ultimate,Premium_Features,Equip_Cost,Room_Cost,Total,First_Name,Last_Name,Email) VALUES (?,?,?,?,?,?,?,?,?,?,?,?,?,?)");
$stmt->bind_param("ssssssssssssss",$NoR,$CC,$SD,$HD,$pack1,$pack2,$pack3,$premC,$equipC,$roomC,$totalC,$fname,$lname,$emailV);
if(isset($_POST['number_rooms'])){ $NoR = $_POST['number_rooms'];$_SESSION['nRooms'] = $NoR; $stmt->execute();}
if(isset($_POST['current_cost'])){ $CC = $_POST['current_cost']; $stmt->execute();}
if(isset($_POST['sd'])){ $SD = $_POST['sd']; $stmt->execute();}
if(isset($_POST['hd'])){ $HD = $_POST['hd']; $stmt->execute();}
if(isset($_POST['family'])){ $pack1 = $_POST['family']; $stmt->execute();}
if(isset($_POST['entertainment'])){ $pack2 = $_POST['entertainment']; $stmt->execute();}
if(isset($_POST['ultimate'])){ $pack3 = $_POST['ultimate']; $stmt->execute();}
if(isset($_POST['premium'])){ $premC = $_POST['premium']; $stmt->execute();}
if(isset($_POST['equipCost'])){ $equipC = $_POST['equipCost'];$_SESSION['pEquip'] = $equipC; $stmt->execute();}
if(isset($_POST['roomCost'])){ $roomC = $_POST['roomCost'];$_SESSION['pRoom'] = $roomC;$stmt->execute();}
if(isset($_POST['total'])){ $totalC = $_POST['total'];$_SESSION['pTotal'] = $totalC;$stmt->execute();}
if(isset($_SESSION['fname'])){$fname = $_SESSION['fname']; $stmt->execute();}
if(isset($_SESSION['lname'])){$lname = $_SESSION['lname']; $stmt->execute();}
if(isset($_SESSION['email'])){$emailV = $_SESSION['email']; $stmt->execute();}
mysqli_close($connect);

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更新

<script type="text/javascript">
    window.onload = function pageRedirect(){
        window.location="fForm.php";
    }
</script>

Answer 1

在一个周末撞墙后，我发现了问题。这个问题非常简单。

$POST()

vs

$_POST()

一个非常小的错字导致了我的

if(isset($_SESSION['email'])){$emailV = $_SESSION['email']; $stmt->execute();}

返回false而不是执行语句。我这是一个非常小的愚蠢错误。我想接下来的问题是为什么Chrome会纠正这个而不是IE？

IE 10和Firefox与phpmyadmin有关

1 个答案: