Question

好的，我正在尝试基本上将两个数据库连接到我的index.php文件，然后使用其中一个数据库来记录用户，并使用其中一个数据库来存储用户的会话。

我无法弄清楚如何存储用户的会话。我想要做的是让用户信息显示，如电子邮件和用户名这样的东西，然后当他们退出时，我希望该信息随会话消失，但目前当用户登录信息时，请保持说明旧用户并没有改变。

我在下面提供了我的代码。在我的代码中，当我提到像它的数据库这样的会话时，因为我创建了一个名为session的数据库和表，而我的另一个数据库被称为数据库，该表称为admin。

索引

<?php
 session_start();
$servername = "localhost";
$username = "root";
$password = "****";
$dbname = "database";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
     die("Connection failed: " . $conn->connect_error);
} 


if($_SERVER["REQUEST_METHOD"] == "POST") {
// username and password sent from form

$myusername = mysqli_real_escape_string($db,$_POST['username']);
$mypassword = mysqli_real_escape_string($db,$_POST['password']);

$sql = "SELECT id FROM admin WHERE username = '$myusername' and passcode = '$mypassword'";
$result = mysqli_query($db,$sql);
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
$active = $row['active'];

$count = mysqli_num_rows($result);

// If result matched $myusername and $mypassword, table row must be 1 row

if($count == 1) { 
$session_id = session_id(); 
$sql = "INSERT INTO session(session_id,username) VALUES('$session_id','$myusername')";
mysqli_query($db,$sql); 
header("Location: test2.php");
}else {
         $error = "";
      }
   }
?>

配置

<?php
   define('DB_SERVER', 'localhost');
   define('DB_USERNAME', 'root');
   define('DB_PASSWORD', '******');
   define('DB_DATABASE', 'database');
   $db = mysqli_connect(DB_SERVER,DB_USERNAME,DB_PASSWORD,DB_DATABASE);
?>

会话

<?php
 include('config.php');
 session_start();

 $user_check = $_SESSION['myusername'];

 $ses_sql = mysqli_query($db,"select username from admin where username = '$user_check' ");

 $row = mysqli_fetch_array($ses_sql,MYSQLI_ASSOC);

 $login_session = $row['username'];

 ?>

测试2页面（这是我要登录的页面，因此它显示用户信息。）

<?php
 session_start();
 include("config.php");

$servername = "localhost";
$username = "root";
$password = "*****";
$dbname = "database";
$dbname2 = "session";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname, $dbname2);
// Check connection
if ($conn->connect_error) {
     die("Connection failed: " . $conn->connect_error);
} 

$session_id = session_id(); 

$sql = "SELECT id, username, passcode, email, Address, City, Country, Zip, FirstName, LastName, About FROM admin WHERE username = (SELECT username FROM session WHERE session_id = '$session_id')";

$result = $conn->query($sql);
$row = $result->fetch_assoc();

?>

Answer 1

正如我在评论中所说：

“基本上，您需要做的是将一个会话数组分配给一个post数组，然后将该会话传递给其他页面（并在WHERE子句中查询），然后在注销时销毁该会话。” EM>

所以这是你可以使用的逻辑，并作为一个基本的例子：

旁注：

我很可能需要花更多的时间来检查整个代码来修复它。这更容易/更快。

<?php session_start(); $_POST['user'] = "John"; // Take the POST array from your named input if (!isset($_SESSION['var'])) { $_SESSION['var'] = $_POST['user']; } else { echo "It seems the session is already set " . $_SESSION['var']; } $username = $_SESSION['var']; echo $username;

...然后检查会话是否在后续页面中设置并应用相同的逻辑。

还要留意你提问的评论。

销毁会话的参考：

http://php.net/manual/en/function.session-destroy.php

尝试将两个数据库连接到php文件并存储用户会话

1 个答案: