Question

我有这组代码，允许我的表单保留存储在表字段中的值。

<?php 
    $playerpositions = Array("Coach", "Assistant Coach", "Goalkeeper", "Defense", "Midfield", "Forward");
?>
<select name="playerposition" id="playerposition" class="input-field-login2" tabindex="1">
   <option value="-1">Select to Change</option>
   <?php
       foreach($playerpositions as $v) {
           $selected = ($row_player['plyPosition']===$v) ? "selected" : "";
           echo "<option value='$v' $selected>$v</option>";
       }
   ?>
</select>

我现在的问题是，可以有一个阵列 $playerpositions = Array("Coach", "Assistant Coach", "Goalkeeper", "Defense", "Midfield", "Forward");

如下所示是动态的

$playerpositions = Array(while ($row_playersa = mysqli_fetch_assoc($result_playersa)) {
    $playersa[] = $row_playersa;
});

这可能吗？因为我想要做的不是将数组项硬编码，我希望它们从表中拉出来。还是有另一种方法可以做到这一点吗？

Answer 1

对这些类型的东西进行硬编码通常是最后的选择。如果您需要在其他地方实现相同的下拉菜单，该怎么办？从数据库表中存储和检索是有意义的，因为您可以在一个地方修改类型并在其他地方引用它们，而无需在许多地方复制，粘贴和维护相同的代码。

但是，你不能像这样构建一个数组。你会这样做的方式是：

// example code, not real, assume it produces
// array("Coach", "Assistant Coach", "Goalkeeper", "Defense", "Midfield", "Forward");

$someQuery = "SELECT * FROM `player_positions`";
$playerPositions = $db->execute($someQuery);

// other code...

// Iterate through your playerPositions and produce your options.
foreach ($playerPositions as $v) {
    echo "<option value='$v' $selected>$v</option>";
}

Answer 2

是

$playerposition = array();

while ($row_playersa = mysqli_fetch_assoc()) {
    $playerposition [] = $row_playersa['name'];
}

foreach($playerposition as $position){
    $selected = ($player_row[$plyPosition]===$position) ? "selected" : null;
    echo '<option value="'. $position .'" ' . $selected . '>'. $position .'</option>';
}

是否可以使数组的元素动态化？

2 个答案: