Question

我必须计算可被5整除的数字。

这是我的代码，

$num = array(4, 25, 60, 7, 8);

foreach ($num as $numbers) {
    if (($numbers % 5) == 0) {
        echo count($numbers); 
    }
}

上述程序的输出为11.但输出应为2.请给我解决方案。提前谢谢。

Answer 1

你也可以这样使用，

function divisibleby5($var){
 return $var % 5 == 0;
}

$num = array(4, 25, 60, 7, 8);
echo count(array_filter($num,'divisibleby5');

Answer 2

$nums = array(4, 25, 60, 7, 8);

仅计算：

- 基本：

$count = 0;
foreach ($nums as $num) {
    if ( $num % 5 == 0 ) $count++;
}

- 使用类型进行播放：

$count = 0;
foreach ($nums as $num) {
    $count += !($num % 5);
}

^{$num % 5返回一个整数，!($num % 5)返回一个布尔值，但因为它被用作+运算符的操作数，false和{{ 1}}表现得像true和0。}

- 使用1的功能版：

array_reduce

要过滤商品，请使用名为$count = array_reduce($nums, function($c, $i) { return $c + !($i % 5); });的商品：

array_filter

并根据需要计算之后的项目数：

$result = array_filter($nums, function ($i) { return $i % 5 == 0; });

Answer 3

我认为你需要做更多类似的事情。

$num = array(4, 25, 60, 7, 8);
$numbers=array();

foreach( $num as $number ) {
    if( $number % 5  == 0 ) $numbers[]=$number;
}
echo count( $numbers );

或者使用array_walk和自定义回调函数

function mod5($item,$key,$arr){
    if($item %5==0)$arr[]=$item;
}
array_walk( $num,'mod5',&$numbers);
echo count($numbers);

Answer 4

此处输出为1和1.不是11（十一）你可以尝试一下

 echo count($numbers)."<br>";

你的解决方案：如果在输入if条件

后递增计数变量值，则输出将为2

<?php
$num = array(4, 25, 60, 7, 8);
$count = 0;

foreach($num as $numbers) {

  if (($numbers % 5) == 0) {
    $count++;
  }
}
echo $count;
?>

Answer 5

如果您想要打印数字

canvas.on("mousemove", function(event) {
    var canvasWidth = canvas.outerWidth();
    var canvasHeight = canvas.outerHeight();
    var halfWidth = canvasWidth / 2;
    var halfHeight = canvasHeight / 2;
    var offsetX = canvas.offset().left;
    var offsetY = canvas.offset().top;

    // Main vars
    var mouseX = event.clientX - offsetX;
    var mouseY = event.clientY - offsetY;

    var maxDegree = 20 * Math.PI / 180;

    var rotationZ = 0;
    if (mouseX < halfWidth) {
        rotationZ = -1* (halfWidth - mouseX) * (maxDegree / halfWidth);
    } else {
        rotationZ = (mouseX - halfWidth) * (maxDegree / halfWidth);
    }

    var rotationX = 0;
    if (mouseY < halfHeight) {
        rotationX = -1* (halfHeight - mouseY) * (maxDegree / halfHeight);
    } else {
        rotationX = (mouseY - halfHeight) * (maxDegree / halfHeight);
    }

    console.log(rotationZ, rotationX);

    mshFloor.rotation.set(rotationX, 0, rotationZ);
    mshBox.rotation.set(rotationX, 0, rotationZ);
    render();
});

或者如果你只需要点数

$a=array(); //initialized empty array
    $num = array(4, 25, 60, 7, 8); 
    foreach($num as $numbers){ 
        if(($numbers % 5) == 0){ 
            $a=$numbers; //store values into the array
        } 
    }
    echo count($a); // echo the count of the array
echo implode('<br>',$a);

回显$ a

PHP计数功能

5 个答案: