我正在尝试为mysql中的count计算一个动态函数:
的functions.php:
function countEntries($table, $where = '', $what = '')
{
if (!empty($where) && isset($what)) {
$q = "SELECT COUNT(*) FROM " . $table . " WHERE " . $where . " = '" . $what . "' LIMIT 1";
} else{
$q = "SELECT COUNT(*) FROM " . $table . " LIMIT 1";
}
$record = query($q);
$total = fetchrow($record);
return $total[0];
}
HTML代码:
<?php echo countEntries("news", "category", "1"); ?>
<?php echo countEntries("post", "type", "Sports"); ?>
但仍然有空白页面没有任何错误!
答案 0 :(得分:0)
你可以尝试一下。
function countEntries($table, $where = '', $what = '')
{
if (!empty($where) && isset($what)) {
$q = "SELECT COUNT(*) AS count FROM " . $table . " WHERE " . $where . " = '" . $what . "' LIMIT 1";
} else{
$q = "SELECT COUNT(*) AS count FROM " . $table . " LIMIT 1";
}
$record = query($q);
$total = fetchrow($record);
return $total['count'];
}
这里给出count(*)的别名,并使用它来访问返回的结果$ total ['count']。 希望它有所帮助。
答案 1 :(得分:0)
您忘记关闭其他事项的第一件事,第二件事只需添加此行&#34; ini_set(&#34; display_errors&#34;,1); &#34;在你的php.this的顶部将显示你的PHP中的错误。
您的代码:
function countEntries($table, $where = '', $what = '')
{
if (!empty($where) && isset($what)) {
$q = "SELECT COUNT(*) FROM " . $table . " WHERE " . $where . " = '" . $what . "' LIMIT 1";
} else
$q = "SELECT COUNT(*) FROM " . $table . " LIMIT 1";
}
$record = query($q);
$total = fetchrow($record);
return $total[0];
}
我的代码:
function countEntries($table, $where = '', $what = '')
{
if (!empty($where) && isset($what)) {
$q = "SELECT COUNT(*) AS count FROM " . $table . " WHERE " . $where . " = '" . $what . "' LIMIT 1";
} else{
$q = "SELECT COUNT(*) AS count FROM " . $table . " LIMIT 1";
}
$record = query($q);
$total = fetchrow($record);
return $total['count'];
}
答案 2 :(得分:0)
谢谢你们,它现在运作良好:
function countEntries($table, $where, $what)
{
if (!empty($where) && isset($what)) {
$q = "SELECT COUNT(*) FROM " . $table . " WHERE " . $where . " = '" . $what . "' LIMIT 1";
} else
$q = "SELECT COUNT(*) FROM " . $table . " LIMIT 1";
$record = mysql_query($q);
$total = mysql_fetch_array($record);
return $total[0];
}
echo countEntries('news', "type", "sport");