Question

void power(float P,float R,float n,float A);
void main()
{
    float A,P,R,n;
    clrscr();
    printf("Enter principal amount:");
    scanf("%f",&A);
    printf("Enter rate of interest:");
    scanf("%f",&R);
    printf("Enter number of years:");
    scanf("%f",&n);
    power(A,R,P,n);
    getch();
}
void power(float A,float R,float P,float n)
{
    int i;
    for(i=1;i<=n;i++)
    {
          A=1+(R*0.01);
          A=A*i;
          A=A*P;
          printf("For year %d, C.I =%f\n",i,A);
    }
}

I put
Principal = 2000
Rate of interest=3
Years=3

我将复利的价值变为负值。错误在A = A * P;必须在不使用幂函数的情况下计算每年的复利

Answer 1

#include<stdio.h>
void power(float P,float R,float n,float A);
void main()
{
    float A,P,R,n;
//    clrscr();
    printf("Enter principal amount:");
    scanf("%f",&A);
    printf("Enter rate of interest:");
    scanf("%f",&R);
    printf("Enter number of years:");
    scanf("%f",&n);
    power(A,R,P,n);
  //  getch();
}
void power(float A,float R,float P,float n)
{
    int i;
        float intr=0;
    for(i=1;i<=n;i++)
    {
        intr=0;
          intr=A*(R/100);
         A=A+intr;
         // A=A*P;
          printf("For year %d, C.I =%f\n",i,intr);
    }
 }

计算复利并显示每年的利息

1 个答案: