Question

我有一个包含与此类似的数据的表

seq Controlid
1   12345
2   12345
5   12345
6   12345
9   12345
10  12345
11  12345
16  12345
1   451251
2   451251
3   451251

我正在寻找一种应用更新命令的方法，该命令可以为特定的Controlid重新排序seq列 - 所以在上述更新后给出Controlid 12345我最终会得到这样的数据：

seq Controlid
1   12345
2   12345
3   12345
4   12345
5   12345
6   12345
7   12345
8   12345
1   451251
2   451251
3   451251

seq columns数据类型为smallint 它始终从1开始。

（我正在使用SQL Server 2008 R2）

Answer 1

试试这个

select 
       row_number() over (partition by Controlid order by seq) as seq, Controlid
 from your_table

编辑：由于您无法使用视图，请尝试此更新

update t1 
set
t1.seq=t2.seq_new from your_table as t1 inner join
(
select 
           row_number() over (partition by Controlid order by seq) as seq_new, seq,
           Controlid
     from your_table
) as t2 on t1.seq=t2.seq and t1.Controlid=t2.Controlid

Answer 2

阅读Madhivanan的评论后，这应该适合你。

CREATE VIEW YOUR_VIEW_NAME
AS
SELECT O.rn,O.Controlid
from 
(SELECT seq
       ,Controlid
       ,ROW_NUMBER() OVER(PARTITION BY Controlid order by Controlid ) as rn

FROM ORDER_SEQ) O

重新排序序号

2 个答案: