我想逐行读取g代码文件，并根据最后的注释，对其执行操作。 g代码来自Slic3r。一些没有特定顺序的示例行看起来像这样：
G1 Z0.242 F7800.000 ; move to next layer (0)
G1 E-2.00000 F2400.00000 ; retract
G1 X0.000 Y30.140 F7800.000 ; move to first skirt point
G1 E0.00000 F2400.00000 ; unretract
G1 X-53.493 Y30.140 E2.14998 F1800.000 ; skirt
G1 X57.279 Y-37.776 E22.65617 ; perimeter
G1 X-52.771 Y-38.586 E56.83128 ; infill
注释始终以分号开头，并且还使用一致的术语，例如周长或填充。理想情况下，脚本会读取行，搜索特定的注释案例，根据该行为执行操作，然后更新文件，然后转到下一行。我对python有些新手，所以我知道这可以通过嵌套if语句的for循环完成，但是我不知道如何设置基于这些关键术语的体系结构。
答案 0 :(得分：1)
我不确定您要完全修改的内容，因此我选择在表示撤消的注释前添加单词'(down)'，并在表示不收缩的注释前添加file_name = "file.gcode" # put your filename here
with open(file_name, 'r+') as f:
new_code = "" # where the new modified code will be put
content = f.readlines() # gcode as a list where each element is a line
for line in content:
gcode, comment = line.strip('\n').split(";") # seperates the gcode from the comments
if 'unretract' in comment:
comment = ' (down) ' + comment
elif 'retract' in comment:
comment = ' (up)' + comment
new_code += gcode + ';' + comment + '\n' # rebuild the code from the modified pieces
f.seek(0) # set the cursor to the beginning of the file
f.write(new_code) # write the new code over the old one
。
G1 Z0.242 F7800.000 ; move to next layer (0)
G1 E-2.00000 F2400.00000 ; (up) retract
G1 X0.000 Y30.140 F7800.000 ; move to first skirt point
G1 E0.00000 F2400.00000 ; (down) unretract
G1 X-53.493 Y30.140 E2.14998 F1800.000 ; skirt
G1 X57.279 Y-37.776 E22.65617 ; perimeter
G1 X-52.771 Y-38.586 E56.83128 ; infill
文件内容现在为：
'U'如果你想修改gcode，让我们说如果评论指示撤消则用'D'替换第一个字母，如果评论指示收缩则用if 'unretract' in comment:
comment = ' (down) ' + comment
elif 'retract' in comment:
comment = ' (up)' + comment
替换，你只需要替换它：
if 'unretract' in comment:
gcode = 'D' + gcode[1:]
elif 'retract' in comment:
gcode = 'U' + gcode[1:]
由此：
G1 Z0.242 F7800.000 ; move to next layer (0)
U1 E-2.00000 F2400.00000 ; retract
G1 X0.000 Y30.140 F7800.000 ; move to first skirt point
D1 E0.00000 F2400.00000 ; unretract
G1 X-53.493 Y30.140 E2.14998 F1800.000 ; skirt
G1 X57.279 Y-37.776 E22.65617 ; perimeter
G1 X-52.771 Y-38.586 E56.83128 ; infill
新文件内容：
X我希望这有帮助！
修改
要回答您获取Y，F和file_name = "file.gcode" # put your filename here
with open(file_name, 'r+') as f:
coordinates = []
content = f.readlines() # gcode as a list where each element is a line
for line in content:
gcode, comment = line.strip('\n').split(";")
coordinate_set = {}
if 'retract' not in comment and 'layer' not in comment:
for num in gcode.split()[1:]:
coordinate_set[num[:1]] = float(num[1:])
coordinates.append(coordinate_set)
值的请求，以下是存储这些值的更新脚本：
print(coordinates)如果你得到[{'X': 0.0, 'F': 7800.0, 'Y': 30.14}, {'E': 2.14998, 'X': -53.493, 'F': 1800.0, 'Y': 30.14}, {'E': 22.65617, 'X': 57.279, 'Y': -37.776}, {'E': 56.83128, 'X': -52.771, 'Y': -38.586}]
：
file_name = "file.gcode"
with open(file_name, 'r+') as f:
new_code = ""
content = f.readlines()
for line in content:
if ';' in line:
try:
gcode, comment = line.strip('\n').split(";")
except:
print('ERROR\n', line)
else: # when there are no comments
gcode = line.strip('\n')
comment = ""
if 'unretract' in comment:
comment = ' (down) ' + comment
elif 'retract' in comment:
comment = ' (up)' + comment
if comment != "":
new_code += gcode + ';' + comment + '\n'
else: # when there are no comments
new_code += gcode + '\n'
f.seek(0)
f.write(new_code)
编辑2
脚本1：
file_name = "file.gcode"
with open(file_name, 'r+') as f:
coordinates = []
content = f.readlines()
for line in content:
if ';' in line:
try:
gcode, comment = line.strip('\n').split(";")
except:
print(' ERROR \n', line, '\n')
else:
gcode = line.strip('\n')
comment = ""
coordinate_set = {}
if 'retract' not in comment and 'layer' not in comment and gcode:
for num in gcode.split()[1:]:
coordinate_set[num[:1]] = float(num[1:])
coordinates.append(coordinate_set)
脚本2：
ERROR Slic3r执行某些奇怪文本的某些行不起作用，这就是print打印的内容。另外，我建议您不要尝试.txt所有坐标，因为这会导致Python崩溃。如果要查看坐标的总体，可以将它们粘贴到单独的with ('coordinates.txt', 'w') as f2:
f2.write(coordinates)
文件中，如下所示：
file_name = "file.gcode"
with open(file_name, 'r+') as f:
new_code = ""
content = f.readlines()
for line in content:
if ';' in line:
try:
gcode, comment = line.strip('\n').split(";")
except:
print('ERROR\n', line)
else: # when there are no comments
gcode = line.strip('\n')
comment = ""
if 'unretract' in comment:
comment = ' (down) ' + comment
elif 'retract' in comment:
comment = ' (up)' + comment
if comment != "":
new_code += gcode + ';' + comment + '\n'
else: # when there are no comments
new_code += gcode + '\n'
f.seek(0)
f.write(new_code)
编辑3
更新了脚本以处理括号中的注释。
脚本1：
file_name = "3Samples_0skin_3per.gcode" # put your filename here
with open(file_name, 'r+') as f:
coordinates = []
content = f.readlines()
for line in content:
if ';' in line:
try:
gcode, comment = line.strip('\n').split(";")
except:
print(' ERROR 1: \n', line, '\n')
elif '(' in line:
try:
gcode, comment = line.strip('\n').strip(')').split("(")
except:
print('ERROR 2: \n', line, '\n')
else:
gcode = line.strip('\n')
comment = ""
coordinate_set = {}
if 'retract' not in comment and 'layer' not in comment and gcode:
for num in gcode.split()[1:]:
if len(num) > 1:
try:
coordinate_set[num[:1]] = float(num[1:])
except:
print('ERROR 3: \n', gcode, '\n')
coordinates.append(coordinate_set)
脚本2：
gameObj.rigidbody2D.AddForce(Vector3.up * 10 * Time.deltaTime); or
gameObj.rigidbody2D.AddForce(Vector3.up * 1000);