我有一个名为item_movement
的表格,其中我存储了购买,销售,客户退回或退回给供应商的库存数量:
------------------------------------------------------------------------
| trans_id | date | trans_type | inventory_id | quantity |
------------------------------------------------------------------------
| 1 | 2016-07-26 | Purchase | 1 | 10 |
------------------------------------------------------------------------
| 2 | 2016-07-26 | Purchase | 2 | 8 |
------------------------------------------------------------------------
| 3 | 2016-07-27 | Sale | 1 | 2 |
------------------------------------------------------------------------
| 4 | 2016-07-28 | Customer Return | 1 | 1 |
------------------------------------------------------------------------
| 5 | 2016-07-29 | Supplier Pullout | 2 | 5 |
------------------------------------------------------------------------
inventory_id是每个库存的标识。
我的代码是:
$conn = new mysqli('localhost', 'username', 'password', 'database');
$query = $_GET['id'];
$item_stock = $conn->query("SELECT * FROM item_movement WHERE `inventory_id` = '%".$query."%' ORDER BY date DESC") or die(mysql_error());
echo '<table class="stock-info-table">
<tr class="center">
<th>Date</th>
<th>Transaction Type</th>
<th>Quantity</th>
<th>Running Stock</th>
</tr>';
while($row = mysqli_fetch_array($item_stock)){
echo '<tr>
<td>'.$row['date'].'</td>
<td>'.$row['trans_type'].'</td>
<td>'.$row['quantity'].'</td>
<td>RUNNING STOCK HERE</td>
</tr>';
}
echo '</table>';
问题: 我还没弄清楚如何显示正在运行的库存,正如您在我的代码中看到的那样。运行库存列应显示每个交易的库存移动数量,如果库存ID 1的采购数量为10,则应显示10.如果销售数量为2,则应显示8(10- 2)。基本上,股票的公式是:购买 - 销售+客户退货 - 供应商提款。 数据还应首先显示最近的交易(DESC),其中运行库存的顺序也应该基于。
编辑: 这是我想要为inventory_id显示的示例数据:
-------------------------------------------------------------------
| Date | Transaction Type | Quantity | Running Stock |
-------------------------------------------------------------------
| 2016-07-29 | Purchase | 5 | 12 |
-------------------------------------------------------------------
| 2016-07-28 | Supplier Pullout | 2 | 7 |
-------------------------------------------------------------------
| 2016-07-27 | Customer Return | 1 | 9 |
-------------------------------------------------------------------
| 2016-07-26 | Sale | 2 | 8 |
-------------------------------------------------------------------
| 2016-07-25 | Purchase | 10 | 10 |
-------------------------------------------------------------------
如果可能,请告诉我。
答案 0 :(得分:2)
您可以通过在变量中保留库存的总计来实现此目的。
我假设你把当前股票保留在某个地方,但是这个例子会为了演示目的而将值从零开始。
同样使用mysqli_fetch_assoc()
,因为它只返回一个列数组,而不是数字数组。
$cur_stock = 0;
$id= $_GET['id'];
$item_stock = $conn->query("SELECT *
FROM `item_movement`
WHERE `inventory_id` = $id
ORDER BY date ASC")
or die(mysql_error());
echo '<table class="stock-info-table">
<tr class="center">
<th>Date</th>
<th>Transaction Type</th>
<th>Quantity</th>
<th>Running Stock</th>
</tr>';
while($row = $conn->fetch_assoc($item_stock)){
switch ($row['trans_type']) {
case 'Purchase' :
case 'Customer Return' :
$cur_stock += (int)$row['quantity'];
break;
case 'Sale' :
case 'Supplier Pullout' :
$cur_stock -= (int)$row['quantity'];
break;
}
echo '<tr>
<td>'.$row['date'].'</td>
<td>'.$row['trans_type'].'</td>
<td>'.$row['quantity'].'</td>
<td>' . $cur_stock . '</td>
</tr>';
}
echo '</table>';
一个例子是
$cur_stock = 0;
$id= $_GET['id'];
$stmt = $conn->prepare("SELECT *
FROM `item_movement`
WHERE `inventory_id` = ?
ORDER BY date ASC");
if ( $stmt === false ) {
echo $conn->error;
exit;
}
$stmt->bind_param('i', $id);
$status = $stmt->execute();
if ( $status === false ) {
echo $conn->error;
exit;
}
$result = $stmt->get_result();
while($row = $result->fetch_assoc($item_stock)){
switch ($row['trans_type']) {
case 'Purchase' :
case 'Customer Return' :
$cur_stock += (int)$row['quantity'];
break;
case 'Sale' :
case 'Supplier Pullout' :
$cur_stock -= (int)$row['quantity'];
break;
}
echo '<tr>
<td>'.$row['date'].'</td>
<td>'.$row['trans_type'].'</td>
<td>'.$row['quantity'].'</td>
<td>' . $cur_stock '</td>
</tr>';
}
echo '</table>';
获取所需输出(即反转)的最简单方法是将结果临时存储在数组中,然后在输出HTML表之前反转数组。
$temp = array();
while($row = $result->fetch_assoc($item_stock)){
switch ($row['trans_type']) {
case 'Purchase' :
case 'Customer Return' :
$cur_stock += (int)$row['quantity'];
break;
case 'Sale' :
case 'Supplier Pullout' :
$cur_stock -= (int)$row['quantity'];
break;
}
$row['running_stock'] = $cur_stock;
$temp[] = $row;
}
// reverse the array
$temp2 = array_reverse($temp);
foreach($temp2 as $row) {
echo '<tr>
<td>' . $row['date'] .'</td>
<td>' . $row['trans_type'] .'</td>
<td>' . $row['quantity'] .'</td>
<td>' . $row['running_stock'] .'</td>
</tr>';
}
echo '</table>';
答案 1 :(得分:1)
为了清晰起见,我一直保持这个答案(如果OP需要获取库存物品的库存数量),但不幸的是这对OP正在寻找的内容不起作用 。这将获得股票,但不会在添加/删除事物时累计运行库存。请参阅@ RiggsFolly的答案,了解如何做到这一点。
通过在mysql中使用GROUP BY和聚合函数,您可以按事务类型总计总计。此查询可以为您提供您正在寻找的股票:
SELECT `inventory_id`, SUM(
CASE
WHEN trans_type IN ('Purchase', 'Customer Return') THEN quantity
WHEN trans_type IN ('Customer Return', 'Supplier Pullout') THEN -1 * quantity
END
) AS `stock`
FROM item_movement
WHERE `inventory_id` LIKE '%".$query."%'
GROUP BY inventory_id
ORDER BY date DESC
首先按查询运行组,获取股票,然后填充数组。在第二个循环中,引用第一个数组。您在此处更新了代码:
<?php
$query = $_GET['id'];
//DO NOT CONCAT QUERY HERE. VERY BAD (See my comment below)
$running_stock = $conn->query("
SELECT `inventory_id`, SUM(
CASE
WHEN trans_type IN ('Purchase', 'Customer Return') THEN quantity
WHEN trans_type IN ('Customer Return', 'Supplier Pullout') THEN -1 * quantity
END
) AS `stock`
FROM item_movement
WHERE `inventory_id` LIKE '%".$query."%'
GROUP BY `inventory_id`") or die(mysqli_error());
$running_stocks = array();
while($row = mysqli_fetch_array($running_stock)){
$running_stocks[ $row['inventory_id'] ] = $row['stock'];
}
//DO NOT CONCAT QUERY HERE. VERY BAD (See my comment below)
$item_stock = $conn->query("SELECT * FROM item_movement WHERE `inventory_id` LIKE '%".$query."%' ORDER BY date DESC") or die(mysqli_error());
echo '<table class="stock-info-table">
<tr class="center">
<th>Date</th>
<th>Transaction Type</th>
<th>Quantity</th>
<th>Running Stock</th>
</tr>';
while($row = mysqli_fetch_array($item_stock)){
echo '<tr>
<td>'.$row['date'].'</td>
<td>'.$row['trans_type'].'</td>
<td>'.$row['quantity'].'</td>
<td>'.(isset($running_stocks[$row['inventory_id']]) ? $running_stocks[$row['inventory_id']] : 0).'</td>
</tr>';
}
echo '</table>';
请注意:您应该binding parameters to your queries。以防止SQL注入。
答案 2 :(得分:1)
您应该能够使用纯SQL解决方案执行此操作。
如果你自己加入表格,匹配的行比较旧,那么你可以让每一行都包含所有旧数量。然后,您可以使用SUM添加旧数量以获得运行总计。
由于某些数量可能实际上是负数,具体取决于交易类型的值,您需要在SUM聚合函数中有条件地将这些数量乘以-1。
SELECT a.`Date`,
a.`Transaction Type`,
a.`Quantity`,
SUM
(
CASE b.`Transaction Type`
WHEN 'Supplier Pullout'
THEN b.`Quantity` * -1
WHEN 'Sale'
THEN b.`Quantity` * -1
ELSE b.`Quantity`
END
) AS `Running Stock`
FROM item_movement a
INNER JOIN item_movement b
ON a.inventory_id = b.inventory_id
AND a.`date` >= b.date
WHERE a.inventory_id = '%".$query."%'
GROUP BY a.`Date`,
a.`Transaction Type`,
a.`Quantity`
ORDER BY a.`date` DESC