Question

我试图从这些数据中获得平衡

Date           Logged      Closed
-------------- ----------- -----------
1-Jan-2016     0           0
2-Jan-2016     8           7
3-Jan-2016     8           8
4-Jan-2016     25          11
5-Jan-2016     20          16
6-Jan-2016     14          13
7-Jan-2016     10          12
8-Jan-2016     9           7
9-Jan-2016     12          12
10-Jan-2016    3           4

预期输出

Date           Logged      Closed      Balance
-------------- ----------- ----------- ----------
1-Jan-2016     0           0           0
2-Jan-2016     8           7           1 
3-Jan-2016     8           8           1
4-Jan-2016     25          11          15
5-Jan-2016     20          16          19
6-Jan-2016     14          13          20
7-Jan-2016     10          12          18
8-Jan-2016     9           7           20
9-Jan-2016     12          12          20
10-Jan-2016    3           4           27

公式为BALANCE = PREVIOUSBALANCE + LOGGED - CLOSED。

示例公式：

Jan 5 Balance (15) = 1(prevBalance) + 25(currentLogged) - 11(currentClosed)

我已经尝试过这个公式，但没有达到预期结果的任何地方。

WITH CTE AS (
SELECT
rownum = ROW_NUMBER() OVER (ORDER BY Date),
Date, Logged, Closed
FROM Table
)

SELECT
(prev.Logged - prev.Closed)+ (a.Logged-a.Closed) as [Balance]
FROM CTE

LEFT JOIN CTE prev ON prev.rownum = CTE.rownum - 1

使用其他参考资料

SQL Server - Calculate current row value using previous row value

http://blog.sqlauthority.com/2013/09/22/sql-server-how-to-access-the-previous-row-and-next-row-value-in-select-statement/

Answer 1

您可以使用窗口函数sum执行此操作。

试试这个：

select 
    t.*,
    sum(logged - closed) over (order by date) balance
from your_table t;

Answer 2

您的答案问题是计算时无法使用前一行的平衡（SQL-Server的一次性原则）。您的问题隐藏了计算所有先前行的总和的要求，按日期排序。

尝试此操作（仅适用于SQL Server 2012及更高版本）

SELECT
    [Date], Logged, Closed,
    SUM(Logged) OVER (ORDER BY [Date] ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)
    - SUM (Closed) OVER (ORDER BY [Date] ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS Balance
FROM
    <<Table>>

对于以前的版本：

SELECT
    t.[Date], t.Logged, t.Closed, sub.L - sub.C AS Balanced
FROM
    <<Table>> t
    CROSS APPLY ( SELECT SUM(Logged) AS L, SUM(Closed) AS c FROM <<Table>> WHERE [Date] <= t.[Date]) AS sub

SQL Server - 从以前的值添加或减去

2 个答案: