Question

我正在进行基于班次的应用，我的工作人员分三班，早上6点到下午2点，下午2点到晚上10点，晚上10点到早上6点（第二天）工作。我需要计算在数据库中记录的每个班次的总工作时间。

  $clientid = $_GET["clientid"];
  $date = $_GET["edate"];
  $shift = $_GET["shift"];

  if(!empty($clientid))
  {
    if($shift=='a')
    {
      $sq =  mysql_query("SELECT * from logusage WHERE etime BETWEEN '6:00:00' AND '14:00:00' AND clientid= '$clientid' AND edate = '$date'",$this->db);
    }
    else if($shift=='b')
    {
      $sq =  mysql_query("SELECT * from logusage WHERE etime BETWEEN '14:00:00' AND '22:00:00' AND clientid= '$clientid' AND edate = '$date'",$this->db);
    }
    else if($shift=='c')
    {
      $sq =  mysql_query("SELECT * from logusage WHERE etime BETWEEN '22:00:00' AND '6:00:00' AND clientid= '$clientid' AND edate= '$date'",$this->db);
    }

每当我尝试访问Shift C时，它只会在当天晚上11:59之前提取数据，因为我也在解析日期。如何更改sql以获取第二天的数据，直到早上6点？

Answer 1

对于第三个，您需要减去小时以获得正确的日期：

SELECT * 
FROM logusage
WHERE etime BETWEEN '22:00:00' AND '6:00:00' AND
      clientid= '$clientid' AND
      date(date_sub(edate, interval 6 hour)) = '$date';

Answer 2

我强烈建议您将EDATE和ETIME作为TIMESTAMP值存储在单个列中，而不是2个单独的列。将时间戳存储为GMT + 00值而不是当地时间也是一种很好的做法 - 但这仅在您当地时间使用DST（白天节省灯）时才有意义。请尝试以下代码：

$clientid = (int)$_GET["clientid"];
$date = $_GET["edate"];
$shift = $_GET["shift"];

if($clientid != 0 AND $date != '')
{
    // I suppose $date is in format YYYY-MM-DD
    list($year,$month,$day) = preg_split('/-/',$date);
    switch($shift)
    {
        case 'a':
            $beg_stamp = mktime(6,0,0,$month,$day,$year);
            $end_stamp = $beg_stamp + 8*3600 - 1;
            break;
        case 'b':
            $beg_stamp = mktime(14,0,0,$month,$day,$year);
            $end_stamp = $beg_stamp + 8*3600 - 1;
            break;
        case 'c':
            $beg_stamp = mktime(22,0,0,$month,$day,$year);
            $end_stamp = $beg_stamp + 8*3600 - 1;
            break;
    }
    if($beg_stamp != '' AND $end_stamp != '') // not strictly needed, if $shift is always valid
        $sq = mysql_query('SELECT * from logusage WHERE clientid = '.$clientid.' AND TIMESTAMP(edate,etime) BETWEEN "'.date('Y-m-d H:i:s',$beg_stamp).'" AND "'.date('Y-m-d H:i:s',$end_stamp).'" ORDER BY edate,etime',$this->db);
}

你从$ end_stamp中减去1，因为SQL谓词BETWEEN是包容性的 - 即 x BETWEEN y AND z 等同于 x＆gt; = y AND x＆lt; = z 你不想抓住属于下一班的工作。

通过时移获取数据 - PHP MYSQL

2 个答案: