Question

我需要比较两个数组中的元素，如下所示：

arr1[0] ? arr2[0]
arr1[1] ? arr2[1]
arr1[2] ? arr2[2]
etc.

我写了一些代码，但是当我尝试在每个数组上比较1000个这样的对象时似乎很慢：

{
   "id":"event707",
   "name":"Custom707",
   "type":"disabled",
   "default_metric":false,
   "participation":"disabled",
   "serialization":"always_record"
}

这就是我的函数的样子（只是两个带有硬编码数据的数组的例子）。

function compare() {
  var step = 0;
  var fruits1 = [{"apple":25},{"bannana":36},{"orange":6}];
  var fruits2 = [{"apple":25},{"bannana":36},{"orange":6}];
  for(var i=0;i<fruits1.length;i++) {
    for(var j=step;j<fruits2.length;j++) {
      console.log("FRUIT1");
      console.log(JSON.stringify(fruits1[i]));
      console.log("FRUIT2");
      console.log(JSON.stringify(fruits2[j]));
      console.log("----------------------");
      if(JSON.stringify(fruits1[i])!== JSON.stringify(fruits2[j])) {
        //do something
      }
      step = step + 1;
      break;
    }
  }
}

Answer 1

没有库的简单功能：

var arr1 = [1,2,3];
var arr2 = [1,2,4];

//This function takes one item, the index of the item, and another array to compare the item with.
function compare(item, index, array2){
  return array2[index] == item;
}

// the forEach method gives the item as first parameter
// the index as second parameter
// and the array as third parameter. All are optional.
arr1.forEach(function(item, index){
  console.log(compare(item, index, arr2));
});

将此与Abdennour TOUMI给出的答案相结合，并且您有一个对象比较方法：）

对于简单对象，您可以使用JSON.stringify(obj1) === JSON.stringify(obj2)。

可以找到有关对象比较的更多信息in this answer

Answer 2

随着DELIMITER $$$ CREATE EVENT autoDayInsert ON SCHEDULE EVERY 15 DAY DO BEGIN SET @dayCounter = 0; WHILE @dayCounter < 15 DO INSERT INTO appointmentDays(`day`) VALUES(NOW() + INTERVAL @dayCounter DAY); SET @dayCounter = @dayCounter +1; END WHILE; END $$$ DELIMITER ;和Object.prototype.compare()的发明，这项工作变得非常简单。数组比较可以处理基本类型项和引用类型项。对象比较浅。让我们看看它是如何运作的;

＆＃13;

Array.prototype.compare()

＆＃13;

Answer 3

使用下划线数组函数。我会去路口

http://underscorejs.org/#intersection

Answer 4

您可以对static课程使用以下Object方法： Object.equals

＆＃13;

Object.equals=function(a,b){if(a===b)return!0;if(!(a instanceof Object&&b instanceof Object))return!1;if(a.valueOf()===b.valueOf())return!0;if(a.constructor!==b.constructor)return!1;for(var c in a)if(a.hasOwnProperty(c)){if(!b.hasOwnProperty(c))return!1;if(a[c]!==b[c]){if("object"!=typeof a[c])return!1;if(!Object.equals(a[c],b[c]))return!1}}for(c in b)if(b.hasOwnProperty(c)&&!a.hasOwnProperty(c))return!1;return!0};

console.log(
    `"[1,2,3] == [1,2,3]" ?`,Object.equals([1,2,3],[1,2,3])
);

console.log(
    `"[{"apple":25},{"bannana":36},{"orange":6}] == [{"apple":25},{"bannana":36},{"orange":6}]" ?`,Object.equals([{"apple":25},{"bannana":36},{"orange":6}], [{"apple":25},{"bannana":36},{"orange":6}])
);

＆＃13;

在javascript中比较数组的有效方法

4 个答案: