我正在尝试从我的数据中过滤掉行:
cid date catcode amtsum
145403 N00000286 2009 F1100 0.500
199228 N00000286 2009 Z5100 4.000
485489 N00000286 2007 B4000 3.300
485547 N00000286 2007 F5100 5.000
488556 N00000286 2007 E4100 2.500
490622 N00000286 2007 F1400 5.000
490924 N00000286 2007 T3100 1.000
490957 N00000286 2007 K1200 5.000
495039 N00000286 2007 Z5300 0.051
496078 N00000286 2008 K1000 13.100
以下是我的一些代码:
#This is data for Barack Obama that I do not want in my data frame. The 'cid' code identifies Obama, I want to remove Obama for the years specified by 'date'.
mask = (campaign_contributions['cid'] == 'N00009638') & (campaign_contributions['date'] >= 2007)
campaign_contributions = campaign_contributions[~mask]
#This is data for John McCain that I do not want in my data frame. The 'cid' code identifies McCain, I want to remove McCain for the years specified by 'date'.
mask1 = (campaign_contributions['cid'] == 'N00006424') & (campaign_contributions['date'] == 2008) & (campaign_contributions['date'] == 2007)
campaign_contributions = campaign_contributions[~mask1]
#This is data for Bob Barr that I do not want in my data frame. The 'cid' code identifies Barr, I want to remove Barr for the years specified by 'date'.
mask2 = (campaign_contributions['cid'] == 'N00002526') & (campaign_contributions['date'] == 2008) & (campaign_contributions['date'] == 2007)
campaign_contributions = campaign_contributions[~mask2]
#This is data for Ralph Nader that I do not want in my data frame.The 'cid' code identifies Nader, I want to remove Nader for the years specified by 'date'.
mask3 = (campaign_contributions['cid'] == 'N00000086') & (campaign_contributions['date'] == 2008) & (campaign_contributions['date'] == 2007)
campaign_contributions = campaign_contributions[~mask3]
上面的代码表示我想要过滤的行。我认为我正在使用〜mask工具不正确。理想情况下,我的最终项目将是没有上面指定行的数据框,即我不希望在我的数据框中显示此信息:
有人可以引导我朝着正确的方向前进吗?
答案 0 :(得分:4)
您可以使用按位和运算符&
来组合蒙版。它可能看起来像这样:
campaign_contributions = campaign_contributions[~mask & ~mask1 & ~mask2 & ~mask3]
或者您也可以使用或运算符|
来执行:
campaign_contributions = campaign_contributions[~(mask | mask1 | mask2 | mask3)]
您可以在this post中找到更多信息。