Question

您好，我试图从2天后解决这个问题，请帮忙。我有一张如下表。我正试图获得交叉表显示

支出

id  name
1   exp1
2   exp2
3   exp3
4   exp4
5   exp5

站

id  name
 1  station1
 2  station2
 3  station3
 4  station4

费用

expenditure_id  station_id  year  month expense
1               1           2015    1   10
1               2           2015    1   20
1               3           2015    1   15
1               4           2015    1   10
1               1           2015    2   20
1               1           2015    3   30
1               1           2015    4   40      
2               1           2015    1   20      
2               1           2015    2   10
2               1           2015    3   20

我正在尝试获得这样的结果

2015年

expenditure station1  station2  station3  station4
exp1        100        20       15        0
exp2        50         0        0         0

其中station1 station2的值将是月费用的总和

Answer 1

这是mysql查询作为您的要求，使用Laravel查询构建器将此查询作为原始查询运行，如果您不知道如何在laravel中运行原始查询让我知道，同时在phpmyadmin / mysql中运行查询客户端，看看它是否为您提供所需的输出。

    SELECT y.expenditure,
      MAX(CASE y.station WHEN 'station1'  THEN y.totalexpense END) 'station1',
      MAX(CASE y.station WHEN 'station2'  THEN y.totalexpense END) 'station2',
      MAX(CASE y.station WHEN 'station3'  THEN y.totalexpense END) 'station3',
      MAX(CASE y.station WHEN 'station4'  THEN y.totalexpense END) 'station4'
   FROM (
        SELECT exp.name AS expenditure,st.name AS station,x.totalexpense
        FROM expenditures AS exp
        LEFT JOIN
        (SELECT expenditure_id,station_id,SUM(expense) as totalexpense
        FROM expenses
        WHERE year = '2015'
        GROUP by expenditure_id,station_id
        )
        AS x ON exp.id = x.expenditure_id
        LEFT JOIN stations AS st  ON x.station_id = st.id
    ) AS y
    GROUP BY y.expenditure

我假设您只有4个电台，如果电台是未知号码，那么您可以使用预备语句并动态创建：

laravel sum和交叉表

1 个答案: