Question

我在多维数组中计算值时寻求一些帮助。

我有一个数组键，就像＆＃34; barrack obama＆＃34; - 值将是一长串数字。

然后下一个数组键可能是＆＃34;另一个名称＆＃34;这些值也是一长串的数字。

最多约10个数组键同样排列。

示例var_dump：

array(10) { ["barack obama"]=> array(4260) { [0]=> string(2) "19" [1]=>    string(2) "92" [2]=> string(2) "27" [3]=> string(2) "55" [4]=> string(2) "56" [5]=> string(2) "57" [6]=> string(4) "1409" [7]=> string(4) "1384" [8]=> string(4) "1362" [9]=> string(4) "1345" [10]=> string(4) "1280" } 
 ["united states"]=> array(5886) { [0]=> string(2) "72" [1]=> string(2) "81" [2]=> string(2) "89" [3]=> string(2) "90" [4]=> string(2) "92" [5]=> string(2) "21" [6]=> string(2) "23" [7]=> string(2) "27" [8]=> string(2) "32" [9]=> string(2) "47" [10]=> string(2) "55" }

如何计算数组键（名称）中唯一值（数字）的出现次数。

所以，如果55岁的话，那就是＆＃34; barack obama＆＃34;和＃34;美国＆＃34;它会得2分。

理想情况下，我只想保留一个或多个键中出现的值，但在我至少得分后，我可以处理。

Answer 1

创建结果数组。然后迭代外部数组，并在循环内部迭代子数组并相应地递增结果数组：

$data = array(
    "barack obama"  =>  array(0,50,150,250,600,900,45,150,1050),
    "tom jones"     =>  array(80,120,150,75,250,80,1100,1900),
    "bob mugabe"    =>  array(50,120,10,0,250,900,600,45,1000,1010),
);    

$results = array(); // create an empty array to store our results
foreach ( $data as $item ): // loop the outer array
    foreach ( $item as $key => $value ): // loop the inner array
        if ( array_key_exists($value,$results) ){ // check if value is already in results, if not set to 1, otherwise increment
            $results[$value] = $results[$value] + 1;
        } else { 
            $results[$value] = 1;
        }

    endforeach;
endforeach;

// show our results array
print "<pre>";
print_r($results);

Answer 2

迭代这样的多维数组：

<?php
$data = array(
    'barack_obama' => array('19', '92', '27', '55', '57', '1409', '1384', '1362', '1345', '1280'),
    'united_states' => array('72', '81', '89', '90', '92', '21', '23', '27', '32', '47', '55'),
);

$aggregator = [];
foreach (array_keys($data) as $i) {
    for ($j = 0, $entryCount = count($data[$i]); $j < $entryCount; $j++) {
        $index = $data[$i][$j];
        $aggregator[$index] = isset($aggregator[$index]) ? $aggregator[$index] + 1 : 1;
    }
}
var_export($aggregator);

结果：

array ( 19 => 1, 92 => 2, 27 => 2, 55 => 2, 57 => 1, 1409 => 1, 1384 => 1, 1362 => 1, 1345 => 1, 1280 => 1, 72 => 1, 81 => 1, 89 => 1, 90 => 1, 21 => 1, 23 => 1, 32 => 1, 47 => 1, )

计算多维php数组中每个键的值的出现次数

2 个答案: