我有一个多维数组对象$ all2 [$ i] [$ j],但未定义,但通过我的laravel sql查询请求收到:
for($i=0; $i<(count($all));$i++){
$uID = HashtagFollow::select('user_id')->where('hashtag_id', $all[$i]->hashtag_id)->where('user_id', '!=', $loggedin->id)->get();
for($j=0;$j<count($uID);$j++){
$all2[$i][$j] = HashtagFollow::select('hashtag_id')->where('user_id', $uID[$j]->user_id)->whereNotIn('hashtag_id', $all)->orderBy('hashtag_id')->get();
}
}
给出以下输出:
0: [[{hashtag_id: 5}], [{hashtag_id: 5}, {hashtag_id: 13}], [{hashtag_id: 2}, {hashtag_id: 13}]]
0: [{hashtag_id: 5}]
1: [{hashtag_id: 5}, {hashtag_id: 13}]
2: [{hashtag_id: 2}, {hashtag_id: 13}]
1: [[{hashtag_id: 5}, {hashtag_id: 13}], [{hashtag_id: 5}], [{hashtag_id: 5}],…]
0: [{hashtag_id: 5}, {hashtag_id: 13}]
1: [{hashtag_id: 5}]
2: [{hashtag_id: 5}]
3: [{hashtag_id: 12}, {hashtag_id: 13}]
2: [[{hashtag_id: 5}, {hashtag_id: 13}], [{hashtag_id: 5}], [{hashtag_id: 12}, {hashtag_id: 13}]]
0: [{hashtag_id: 5}, {hashtag_id: 13}]
1: [{hashtag_id: 5}]
2: [{hashtag_id: 12}, {hashtag_id: 13}]
3: [[{hashtag_id: 5}, {hashtag_id: 13}], [{hashtag_id: 2}, {hashtag_id: 12}, {hashtag_id: 13}],…]
0: [{hashtag_id: 5}, {hashtag_id: 13}]
1: [{hashtag_id: 2}, {hashtag_id: 12}, {hashtag_id: 13}]
2: [{hashtag_id: 5}]
3: [{hashtag_id: 5}, {hashtag_id: 13}]
4: [{hashtag_id: 2}, {hashtag_id: 13}]
5: [{hashtag_id: 12}, {hashtag_id: 13}]
4: [[{hashtag_id: 5}, {hashtag_id: 13}], [{hashtag_id: 5}], [{hashtag_id: 5}],…]
0: [{hashtag_id: 5}, {hashtag_id: 13}]
1: [{hashtag_id: 5}]
2: [{hashtag_id: 5}]
3: [{hashtag_id: 5}, {hashtag_id: 13}]
4: [{hashtag_id: 12}, {hashtag_id: 13}]
5: [[{hashtag_id: 5}], [{hashtag_id: 2}, {hashtag_id: 12}, {hashtag_id: 13}],…]
0: [{hashtag_id: 5}]
1: [{hashtag_id: 2}, {hashtag_id: 12}, {hashtag_id: 13}]
2: [{hashtag_id: 5}, {hashtag_id: 12}, {hashtag_id: 13}]
3: [{hashtag_id: 5}]
4: [{hashtag_id: 2}, {hashtag_id: 13}]
5: [{hashtag_id: 12}, {hashtag_id: 13}]
我现在正在尝试循环此对象数组,并计算每个hashtag_id中有多少。
预期输出: hashtag_id:2计数:2 hashtag_id:5计数:5 hashtag_id:12计数:3 hashtag_id:13计数:6
答案 0 :(得分:0)
您可能要考虑直接查询这些计数。
例如
SELECT hashtag_id, user_id, COUNT(*) AS count
FROM HashtagFollow
GROUP BY hashtag_id, user_id;