Question

我正在尝试编写一个方法findChar（）。此方法将字符和字符串数组作为参数，并打印数组中包含指定参数字符的所有单词。例如

Test                                 Result
String[] words = {"caravan", "car", "van", "bike", "scooter", "vehicle", "bicycle"};

findChar('v', words);  Words containing the letter v : caravan van vehicle
findChar('i', words);  Words containing the letter i : bike vehicle bicycle

我现在得到类似的东西这是一个粗略的想法，但不是100％肯定，因为我还有一周学习java所以请放轻松。

   public static void findChar(Char character, String word) {
   for(String word:words) {
            // Check if it contains the character
            if (word.contains(Character.toString(character))) {
                wordsContainingCharacter.add(word);
            }

    if(.....size() > 0) {
            System.out.println("Words containing the letter " + character + " : " + ....);
        } else {
            System.out.println("Character is not in any word");
        }
    }
}

Answer 1

这应该有效

public static void findChar(char character, String words[]) {
    //ArrayList for putting the matched words
    ArrayList<String> wordsContainingCharacter = new ArrayList<String>();
    for (String word : words) {
        // Check if it contains the character
        if (word.contains(Character.toString(character))) {
            wordsContainingCharacter.add(word);
        }

    }
    //2.check is to be put after the loop
    if (wordsContainingCharacter.size() > 0) {
        System.out.println("Words containing the letter " + character
                + " : " + wordsContainingCharacter);
    } else {
        System.out.println("Character is not in any word");
    }
}

不使用ArrayList的逻辑

    StringBuilder stringOfWords=new StringBuilder();
    for (String word : words) {
        // Check if it contains the character
        if (word.contains(Character.toString(character))) {
            stringOfWords.append(word+" ");
        }

    }
    //2.check is to be put after the loop
    if (stringOfWords.length() > 0) {
        System.out.println("Words containing the letter " + character
                + " : " + stringOfWords);
    } else {
        System.out.println("Character is not in any word");
    }

在数组中查找字符

1 个答案: