Question

#include <stdio.h>
#include <string.h.>


int main()
{
char hurray[] = "Hooray for all of us"; //Character String
char *hurrayptr = hurray;   //Pinter to array hurray
int i = 0; //Used in for loop to display position and character
int d = 0; //Used in printf statement to count the position 
int k;
int count = 0;
int index;
int f = 0;

printf("\tPosition\t Character"); 

while (hurray[i] > 20) { 

    for (i = 0; i < 20; i++) {  

        printf("\n\t hurray[%d]\t\t  %c", d++, *hurrayptr++); 

    }
}

for (k = 0; hurray[k]!= '\0'; k++)      
    if ('a' == hurray[k]) {  //specifies character 'a' is to be counted

        count++;    
    }
        printf("\n'A' occurs %d times in this array\n", count); 

        hurrayptr = strchr(hurray, 'a');
        index = (int)(hurrayptr - hurray);
        f++;

        printf("The letter 'a' was find in hurray[%d]\n", index);

return 0;
}

我试图让它显示数组hurray []中的元素数量，然后它会找到多少次＆＃39; a＆＃39;发生在数组中。然后我需要找到＆＃39; a＆＃39;的索引。发现了。我只能找到第一个＆＃39; a＆＃39;之后它停止了。我该如何解决这个问题？

Answer 1

此代码：

points(0,fun(0),pch=16)
points(Re(polyroot(c(4,3,2,1))[2]),0,pch=16)

仅查找第一个字母。您需要在循环中执行这些步骤：

hurrayptr = strchr(hurray, 'a');
index = (int)(hurrayptr - hurray);
f++;

printf("The letter 'a' was find in hurray[%d]\n", index);

对hurrayptr = strchr(hurray, 'a'); do { index = (int)(hurrayptr - hurray); printf("The letter 'a' was find in hurray[%d]\n", index); hurrayptr = strchr(hurrayptr+1, 'a'); } while (hurrayptr);的第一次调用从字符串的开头开始，循环内部的调用开始查找找到的最后一个实例。

此外，这不是必需的：

strchr

你有一个while (hurray[i] > 20) {循环，它已经打印了所有字符。 for是多余的。

找到字符索引＆＃39; a＆＃39;在数组中

1 个答案: