Question

我正在尝试通过使用2感知器网络来制作XOR门但由于某种原因网络没有学习，当我在图中绘制误差的变化时，误差变为静态水平并在该区域中振荡。

目前我没有对网络添加任何偏见。

import numpy as np

def S(x):
    return 1/(1+np.exp(-x))

win = np.random.randn(2,2)
wout = np.random.randn(2,1)
eta = 0.15

# win = [[1,1], [2,2]]
# wout = [[1],[2]]

obj = [[0,0],[1,0],[0,1],[1,1]]
target = [0,1,1,0]

epoch = int(10000)
emajor = ""

for r in range(0,epoch):
    for xy in range(len(target)):
        tar = target[xy]
        fdata = obj[xy]

        fdata = S(np.dot(1,fdata))

        hnw = np.dot(fdata,win)

        hnw = S(np.dot(fdata,win))

        out = np.dot(hnw,wout)

        out = S(out)

        diff = tar-out

        E = 0.5 * np.power(diff,2)
        emajor += str(E[0]) + ",\n"

        delta_out = (out-tar)*(out*(1-out))
        nindelta_out = delta_out * eta

        wout_change = np.dot(nindelta_out[0], hnw)

        for x in range(len(wout_change)):
            change = wout_change[x]
            wout[x] -= change

        delta_in = np.dot(hnw,(1-hnw)) * np.dot(delta_out[0], wout)
        nindelta_in = eta * delta_in

        for x in range(len(nindelta_in)):
            midway = np.dot(nindelta_in[x][0], fdata)
            for y in range(len(win)):
                win[y][x] -= midway[y]



f = open('xor.csv','w')
f.write(emajor) # python will convert \n to os.linesep
f.close() # you can omit in most cases as the destructor will call it

这是因学习轮数而改变的错误。它是否正确？红色线是我期望错误应该如何变化的线。

我在代码中做错了什么？因为我似乎无法弄清楚导致错误的原因。非常感谢。

提前致谢

Answer 1

这是一个带有反向传播的隐藏层网络，可以自定义运行relu，sigmoid和其他激活的实验。经过几次实验后得出的结论是，网络表现更好，并且更快地达到收敛，而在sigmoid下，损失值波动。这是因为，＆＃34; https://stackoverflow.com/a/25110513＆＃34;。

import numpy as np
import matplotlib.pyplot as plt
from operator import xor

class neuralNetwork():
    def __init__(self):
        # Define hyperparameters
        self.noOfInputLayers = 2
        self.noOfOutputLayers = 1
        self.noOfHiddenLayerNeurons = 2

        # Define weights
        self.W1 = np.random.rand(self.noOfInputLayers,self.noOfHiddenLayerNeurons)
        self.W2 = np.random.rand(self.noOfHiddenLayerNeurons,self.noOfOutputLayers)

    def relu(self,z):
        return np.maximum(0,z)

    def sigmoid(self,z):
        return 1/(1+np.exp(-z))

    def forward (self,X):
        self.z2 = np.dot(X,self.W1)
        self.a2 = self.relu(self.z2)
        self.z3 = np.dot(self.a2,self.W2)
        yHat = self.relu(self.z3)
        return yHat

    def costFunction(self, X, y):
        #Compute cost for given X,y, use weights already stored in class.
        self.yHat = self.forward(X)
        J = 0.5*sum((y-self.yHat)**2)
        return J

    def costFunctionPrime(self,X,y):
        # Compute derivative with respect to W1 and W2
        delta3 = np.multiply(-(y-self.yHat),self.sigmoid(self.z3))
        djw2 = np.dot(self.a2.T, delta3)
        delta2 = np.dot(delta3,self.W2.T)*self.sigmoid(self.z2)
        djw1 = np.dot(X.T,delta2)

        return djw1,djw2


if __name__ == "__main__":

    EPOCHS = 6000
    SCALAR = 0.01

    nn= neuralNetwork()    
    COST_LIST = []

    inputs = [ np.array([[0,0]]), np.array([[0,1]]), np.array([[1,0]]), np.array([[1,1]])]

    for epoch in xrange(1,EPOCHS):
        cost = 0
        for i in inputs:
            X = i #inputs
            y = xor(X[0][0],X[0][1])
            cost += nn.costFunction(X,y)[0]
            djw1,djw2 = nn.costFunctionPrime(X,y)
            nn.W1 = nn.W1 - SCALAR*djw1
            nn.W2 = nn.W2 - SCALAR*djw2
        COST_LIST.append(cost)

    plt.plot(np.arange(1,EPOCHS),COST_LIST)
    plt.ylim(0,1)
    plt.xlabel('Epochs')
    plt.ylabel('Loss')
    plt.title(str('Epochs: '+str(EPOCHS)+', Scalar: '+str(SCALAR)))
    plt.show()

    inputs = [ np.array([[0,0]]), np.array([[0,1]]), np.array([[1,0]]), np.array([[1,1]])]
    print "X\ty\ty_hat"
    for inp in inputs:
        print (inp[0][0],inp[0][1]),"\t",xor(inp[0][0],inp[0][1]),"\t",round(nn.forward(inp)[0][0],4)

结束结果：

the gradient of sigmoids becomes increasingly small as the absolute value of x increases

X       y       y_hat
(0, 0)  0       0.0
(0, 1)  1       0.9997
(1, 0)  1       0.9997
(1, 1)  0       0.0005

训练后获得的体重是：

nn.w1

[ [-0.81781753  0.71323677]
  [ 0.48803631 -0.71286155] ]

nn.w2

[ [ 2.04849235]
  [ 1.40170791] ]

我发现以下youtube系列对于理解神经网络非常有帮助：

我知道的只有很少，也可以在这个答案中解释。如果你想更好地理解神经网络，那么我建议你通过以下链接：Neural networks demystified

Answer 2

每个时期计算的误差应该是所有平方误差的总和（即每个目标的误差）

import numpy as np
def S(x):
    return 1/(1+np.exp(-x))
win = np.random.randn(2,2)
wout = np.random.randn(2,1)
eta = 0.15
# win = [[1,1], [2,2]]
# wout = [[1],[2]]
obj = [[0,0],[1,0],[0,1],[1,1]]
target = [0,1,1,0]    
epoch = int(10000)
emajor = ""

for r in range(0,epoch):

    # ***** initialize final error *****
    finalError = 0

    for xy in range(len(target)):
        tar = target[xy]
        fdata = obj[xy]

        fdata = S(np.dot(1,fdata))

        hnw = np.dot(fdata,win)

        hnw = S(np.dot(fdata,win))

        out = np.dot(hnw,wout)

        out = S(out)

        diff = tar-out

        E = 0.5 * np.power(diff,2)

        # ***** sum all errors *****
        finalError += E

        delta_out = (out-tar)*(out*(1-out))
        nindelta_out = delta_out * eta

        wout_change = np.dot(nindelta_out[0], hnw)

        for x in range(len(wout_change)):
            change = wout_change[x]
            wout[x] -= change

        delta_in = np.dot(hnw,(1-hnw)) * np.dot(delta_out[0], wout)
        nindelta_in = eta * delta_in

        for x in range(len(nindelta_in)):
            midway = np.dot(nindelta_in[x][0], fdata)
            for y in range(len(win)):
                win[y][x] -= midway[y]

     # ***** Save final error *****
     emajor += str(finalError[0]) + ",\n"


f = open('xor.csv','w')
f.write(emajor) # python will convert \n to os.linesep
f.close() # you can omit in most cases as the destructor will call it

神经网络XOR门不学习

2 个答案: