#include <iostream>
#include <functional>
class Base
{
public:
virtual ~Base() {}
virtual void f1() const {std::cout<<"Base::f1() called"<<std::endl;}
virtual void f1(int) const {std::cout<<"Base::f1(int) called"<<std::endl;}
virtual void f2() const {std::cout<<"Base::f2() called"<<std::endl;}
};
class Derived : public Base
{
public:
virtual ~Derived() {}
void f1() const {std::cout<<"Derived::f1() called"<<std::endl;}
};
int main()
{
Base base;
Derived derived;
auto func1 = std::bind(static_cast<void(Base::*)()const>(&Base::f1), std::cref(base));
func1();
auto func2 = std::bind(static_cast<void(Derived::*)()const>(&Derived::f1), std::cref(derived));
func2();
auto func3 = std::bind(&Base::f2, std::cref(base));
func3();
auto func4 = std::bind(&Derived::f2, std::cref(derived));
func4();
auto func5 = std::bind(static_cast<void(Base::*)(int)const>(&Base::f1), std::cref(base), std::placeholders::_1);
func5(1);
auto func6 = std::bind(static_cast<void(Derived::*)(int)const>(&Derived::f1), std::cref(derived), std::placeholders::_1); // error line
func6(2);
return 0;
}
当我尝试构建上面的代码时,gcc会给出以下错误消息。
test.cpp:34:80:错误:类型为'void的static_cast无效 (Derived :: )()const'类型'void(Derived :: )(int)const'
auto func6 = std :: bind(static_cast(&amp; Derived :: f1), std :: cref(derived),std :: placeholders :: _ 1);
我想知道是否有任何方法可以通过类Base::f1(int)
绑定Derived
(在此成功绑定func6
)。
任何帮助表示赞赏。
答案 0 :(得分:1)
如何使用&Derived::Base::f1
代替&Derived::f1
?
我的意思是
auto func6 = std::bind(static_cast<void(Derived::*)(int)const>(&Derived::Base::f1), std::cref(derived), std::placeholders::_1);
正如Oktalist(谢谢)所建议的那样,您也可以使用&Base::f1
。
它更简单。