Question

我正在使用rails中的简单动作调用，我找不到有什么问题以及为什么许多解决方案在我的情况下不起作用。我提到我是来自Java世界的新人。

问题是这样的：
我希望在我的视图中有一个指向控制器操作的按钮，这是一个更改表中列的操作。

的routes.rb

发布'punch / userout'=＆gt; 'punch #userout'，：as =＆gt; ：userout

查看： punch \ out.erb

 <%= link_to('Out', userout_path, method: :post)  %>

controller：punch_controller.rb

  
class PunchController  ApplicationController
    before_filter :authorize_admin, only: :index
    layout 'application'
    layout false, :except  => :new 

  # GET method to get all products from database
  def index
    #@punchins = Punchin.all
    @filterrific = initialize_filterrific(
        Punchin,
        params[:filterrific]
    ) or return

    @punchins = @filterrific.find.page(params[:page])

    respond_to do |format|
      format.html
      format.js
    end

    rescue ActiveRecord::RecordNotFound => e
    # There is an issue with the persisted param_set. Reset it.
    puts "Had to reset filterrific params: #{ e.message }"
    redirect_to(reset_filterrific_url(format: :html)) and return
  end

  # GET method for the new product form
  def new
    @punchin = Punchin.new
     if current_user.admin
       redirect_to root_path
=begin
     elsif current_user.punched_in
       redirect_to punch_out_path
=end
     end
  end

  # POST method for processing form data
  def create
    #@punchin.user_id = current_user.id
    #@punchin = Punchin.new(punch_params)
    @punchin = current_user.punchins.build(punch_params)
    @punchin.server_time = Time.now.strftime("%Y-%m-%d %H:%M")
    #@punchin.is_punched = true;

    #get current user from punchin
    @user = @punchin.user
    #set punched on user with true
    @user.punched_in = true;
    #update user
    @user.save
    #@punchin.user.punched_in = true;
    if @punchin.save
      flash[:notice] = 'Punched In!'
      # Tell the Punchinailer to send a notification email after save
      PunchinMailer.punchin_email(@punchin).deliver_later

      redirect_to punch_in_path
    else
      flash[:error] = 'Failed to edit Punch!'

      render :new
    end
  end

  # PUT method for updating in database a product based on id
  def update
    @punchin = Punchin.find(params[:id])
    if @punchin.update_attributes(punch_params)
      flash[:notice] = 'Punchin updated!'
      redirect_to root_path
    else
      flash[:error] = 'Failed to edit Punchin!'
      render :edit
    end
  end

  # DELETE method for deleting a product from database based on id
  def destroy
    @punchin = Punchin.find(params[:id])
    if @punchin.delete
      flash[:notice] = 'Punchin deleted!'
      redirect_to root_path
    else
      flash[:error] = 'Failed to delete this Punchin!'
      render :destroy
    end
  end

  private
  # we used strong parameters for the validation of params
  def punch_params
    params.require(:punchin).permit(:server_time, :address_geoloc, :work_type, :work_desc, :user_id)
  end

  def show
    # method level rendering
    @punchin = Punchin.find(params[:id])
  end

  #when punched in
  def in
  end 

  def userout
    if user_signed_in?
      current_user.update_attributes(:punched_in => false)
    else
      redirect_to new_user_session_path, notice: 'You are not logged in.'
    end
  end
end

并且对于信息：one punch belongs_to：user and users has_many：punches

我在users表中有一个列，其中包含punched_in：true / false，当我从视图中单击链接/按钮时，我只希望将该列设置为false。

我尝试了很多解决方案，包括link_to，button_to，不同路线等。在这种情况下，我收到此错误：

找不到PunchController
的动作'userout'

在其他情况下，我的按钮工作但无法达到我想要的操作。

谢谢！

Answer 1

您的行为是私密的。将它移到专线上方，它将起作用

Answer 2

我为你做了一些重构

def userout
  if user_signed_in?
    current_user.update_attributes(punched_in: false)
    redirect_to punch_out_path, notice: "You've been punched out" # what path do you want to redirect to?
  else
    redirect_to new_user_session_path, notice: 'You are not logged in.'
  end
end

你可以运行＆＃34; rake routes＆＃34;从命令行。路线在哪里？

当您单击链接时，rails控制台会说什么。

单击按钮Rails时，从视图中调用自定义控制器操作

2 个答案: