Question

我有如下所示的表格，我想在每周的所有5周工作日内捕获员工是否工作。如果员工只工作3天，那么我想显示他/她工作的3天的工作时间，并为2个缺失的日子分配0：

UID        DT         HOURS_WORKED
Mike      07/4/16          5
Mike      07/5/16          8
Mike      07/7/16          4

这是此方案的预期结果

UID        DT         HOURS_WORKED
Mike      07/4/16          5
Mike      07/5/16          8
Mike      06/6/16          0
Mike      07/7/16          4
Mike      07/8/16          0

所以当他们跳过当天的工作时我想把0。我不想显示周末。谢谢你的帮助

select UID, DT, HOURS_WORKED from my table

Answer 1

构建一个日期cte，其中包含一周内的所有日期，并在此表上执行外部联接，以便在员工在给定工作日不工作时显示0。

with x as (select cast('2016-07-01' as date) dt
           union all
           select dateadd(dd,1,dt) from x where dt < '2016-07-31')
select e.uid, t.dt, coalesce(e.hours_worked,0) hours_worked
from (select * from x where datepart(dw,dt) between 2 and 6) t
left join emp_table e on e.dt = t.dt

Answer 2

我增强了@vkp的答案，使其更通用，（如果你真的很挑剔我们需要处理边缘情况，在第一周或上周的某些天可能会落入不同年份）

在这里，我添加了使用Datefirst设置更改一周的第一天的功能。更多关于Datefirst MSDN：https://msdn.microsoft.com/en-us/library/ms181598.aspx

/*  Setup Test Data
Drop Table #T1 

Create Table #T1 ( UID Varchar(10), Dt   Date, Hrs int )

insert into #T1 Values 
( 'Mike' , GetDate()   , 8 ) ,    -- Sat 07/23
( 'Mike' , GetDate()-1 , 8 ) ,
( 'Mike' , GetDate()-2 , 8 ) ,
( 'Mike' , GetDate()+3 , 8 )      -- Tue 07/26
( 'John' , GetDate()   , 8 ) ,    -- Sat 07/23
( 'John' , GetDate()-1 , 8 ) ,
( 'John' , GetDate()-2 , 8 ) ,
( 'John' , GetDate()+3 , 8 ) 


 insert into #T1 Values 
( 'Mike' , GetDate() - 206   , 8 ) ,   --- One Date for Last Year 12/30 to Test Edge Case

-- select * , DatePart( WEEK, Dt) from #T1
*/

- 创建帮助电视功能以获取一年中某一周的日期

ALTER FUNCTION GetDates
(
    @WK int ,
    @yr varchar(5) = ''
)


RETURNS 
    @Table_Var TABLE 
    (
        DD int, 
        Dt Date,
        Wk int
    )
AS

BEGIN

IF @yr = ''  SET @yr  = YEAR(Getdate()) -- If Year is Blank then Default to current year

Declare @LastDateOfYr Date = RTRIM(@YR)+'-12-31' -- Last Day of the year
Declare @LastDayOfYr Int = CAST(Datename(dy, @LastDateOfYr ) as int) -- No.of Days in the Year to Handle Leap Yrs

;WITH Dates as 
(
--  SELECT 0 as DD          ,  DATEADD(D, 0, @yr )        as Dt  , DatePart( WEEK,  DATEADD(D, 0 , @yr )) as Wk
    SELECT Datepart( DAYOFYEAR,DateAdd(D, (@WK-2)*7, @yr) ) as DD , DATEADD(D, (@WK-2)*7, @yr )  as Dt  ,  @WK-2 as Wk -- Initial values for the Recursive CTE.
    UNION ALL
    SELECT Dates.DD+1 as DD ,  DATEADD(D, Dates.DD, @yr )         , DatePart( WEEK,DATEADD(D, Dates.DD, @yr )) from Dates where Dates.DD <= @LastDayOfYr
    AND Wk <= @WK + 1  -- Terminator for Recursion
) 

INSERT INTO @Table_Var 
SELECT 
        DD , 
        Dt ,
        Wk 
FROM Dates as A 
WHERE A.Wk = @WK
OPTION (MAXRECURSION 21)  -- At any point we dont use CTE For more than 3 Weeks (one week actually). If the CTE is changed by using the commented out Initializer inside the CTE Above then this number has to change accordingly

  RETURN 

END
GO

查询：

SET DATEFIRST 1  -- Make Monday as First Day of Week. The default is Sunday.

Select B.* , A.* , ISNULL(T.Hrs,0) Hours_Worked
FROM
        ( SELECT Distinct UID, 
                DatePart( WEEK, Dt) as WK , 
                DatePart( YEAR, Dt) as Yr 
          FROM #T1  
        ) A 
CROSS APPLY dbo.GetDates(A.WK, A.Yr ) B -- Helper Function Used to apply 
LEFT OUTER JOIN #T1 T ON B.Dt = T.Dt

计算每周工作时间并使用SQL排除周末

2 个答案: