Question

我想获得2个日期时间之间经过的小时数，但不包括周末。

所以我想说我有2014-03-28 07:45:00（这是星期五）和2014-04-04 09:45:00（这是星期五）我想弄清楚两个日期之间经过了多少小时但排除了周末。

我不知道如何继续，但我找到了http://www.codersrevolution.com/blog/SQL-Server-How-Many-WorkWeek-Days-In-Date-Range

找工作日的链接

Answer 1

创建一个功能：

create function f_hour_diff (@date1 datetime,@date2 datetime)
returns int
as
begin
    -- if @date1 happens on the weekend, set to next Monday 12AM
    if datepart(weekday,@date1) = 1
        set @date1 = dateadd(day,datediff(day,0,@date1),1)
    if datepart(weekday,@date1) = 7
        set @date1 = dateadd(day,datediff(day,0,@date1),2)

    -- if @date2 happens on the weekend, set to previous Saturday 12AM
    -- to count all of Friday's hours
    if datepart(weekday,@date2) = 1
        set @date2 = dateadd(day,datediff(day,0,@date2),-2)
    if datepart(weekday,@date2) = 7
        set @date2 = dateadd(day,datediff(day,0,@date2),-1)

    -- return number of hours between @date1 and @date1
    -- subracting the number of weeks between * 48 to take out weekends
    declare @return int
    set @return = datediff(hour,@date1,@date2)-(datediff(week,@date1,@date2)*48)

    -- Return the result of the function
    return @return

end
go

调用函数：

select dbo.f_hour_diff('2014-03-28 07:45:00','2014-04-04 09:45:00')

获取不包括周末的小时数

1 个答案: