我有以下收集......
[{
"_id":"abcd1234",
"Date" :{"$date":1430418601000},
"Count":{
"hr1":0,
"hr2":20,
"hr3":1,
"hr4":4,
"hr5":0,
}
},
{
"_id":"abcd1234",
"Date" :{"$date":1430505001000},
"Count":{
"hr1":2,
"hr2":15,
"hr3":15,
"hr4":0,
"hr5":1,
}
}
]
我想汇总这些日期的计数,所以总计数就像......
{"hr1":2,
"hr2":35,
"hr3":16,//......so on
}
mongodb有可能吗?我不太了解mongo,如果有人可以指导我这个查询会有帮助...
答案 0 :(得分:0)
运行以下聚合管道应该可以获得所需的结果:
db.collection.aggregate([
{
"$group": {
"_id": null,
"hr1": { "$sum": "$Count.hr1" },
"hr2": { "$sum": "$Count.hr2" },
"hr3": { "$sum": "$Count.hr3" },
"hr4": { "$sum": "$Count.hr4" },
"hr5": { "$sum": "$Count.hr5" }
}
}
])
指定_id
null
值将计算所有输入文档的累计值。