答案 0 :(得分:2)
您可以通过执行子查询的透视来实现结果,该子查询标识每个Category
- Product
组的最新记录。
SELECT t1.Category,
MAX(CASE WHEN t1.Product = 'pen' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Pen,
MAX(CASE WHEN t1.Product = 'pencil' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Pencil,
MAX(CASE WHEN t1.Product = 'glue' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Glue
FROM yourTable t1
INNER JOIN
(
SELECT Category, Product, MAX(timestamp) AS timestamp
FROM yourTable
GROUP BY Category, Product
) t2
ON t1.Category = t2.Category AND
t1.Product = t2.Product AND
t1.timestamp = t2.timestamp
GROUP BY t1.Category
请按照以下链接查看正在运行的演示:
答案 1 :(得分:0)
试试这个:
select
Category,
max(case when Product = 'pen' then concat(`Flag`, '(productid-', Product_ID, ')') else null end) as `Pen`,
max(case when Product = 'pencil' then concat(`Flag`, '(productid-', Product_ID, ')') else null end) as `Pencil`,
max(case when Product = 'glue' then concat(`Flag`, '(productid-', Product_ID, ')') else null end) as `Glue`
from (
select t1.*
from yourtable t1
join (
select Product, Category, max(`timestamp`) as `timestamp`
from yourtable
group by Product, Category
) t2 on t1.Product = t2.Product and t1.`timestamp` = t2.`timestamp` and t1.Category = t2.Category
) t
group by Category