假设我有桌子'组织'有两列'姓名'和'角色'字段'名称'包含一个字符串,类似的'角色'可以是以下列表中的字符串:['管理员','主持人','用户']。
我想执行一个查询,向我打印按角色排序的用户。 例如,有以下起始表:
+++++++++++++++++++++++
+ Name + Role +
+++++++++++++++++++++++
+ Sara + User +
+ Tony + Admin +
+ John + User +
+++++++++++++++++++++++
我想获得以下查询:
++++++++++++++++++++++++++++++++++++++++
+ Admin + Moderator + User +
++++++++++++++++++++++++++++++++++++++++
+ Tony + NULL + Sara +
+ NULL + NULL + John +
++++++++++++++++++++++++++++++++++++++++
我到目前为止提出的最佳解决方案如下,但我希望有一个更紧凑的解决方案。我需要的是分离列然后重新加入它们,但我不知道如何做到这一点......
SELECT CASE WHEN Role = 'Admin' THEN Name END AS 'Admin',
CASE WHEN Role = 'Moderator' THEN Name END AS 'Moderator',
CASE WHEN Role= 'User' THEN Name END AS 'User'
FROM Organization;
++++++++++++++++++++++++++++++++++++++++
+ Admin + Moderator + User +
++++++++++++++++++++++++++++++++++++++++
+ NULL + NULL + Sara +
+ Tony + NULL + NULL +
+ NULL + NULL + John +
++++++++++++++++++++++++++++++++++++++++
答案 0 :(得分:3)
要执行此操作,您可以使用等效的ROW_NUMBER
和GROUP BY
计算的RowNumber列:
SELECT
MAX(CASE WHEN Role = 'Admin' THEN Name END) AS `Admin`,
MAX(CASE WHEN Role = 'Moderator' THEN Name END) AS `Moderator`,
MAX(CASE WHEN Role = 'User' THEN Name END) AS `User`
FROM (
SELECT *
,@row_num := IF(@prev_value=concat_ws('',t.Role),@row_num+1,1) AS RowNumber
,@prev_value := concat_ws('',t.Role)
FROM Organization t,
(SELECT @row_num := 1) x,
(SELECT @prev_value := '') y
ORDER BY t.Role
) AS sub
GROUP BY RowNumber
的 SqlFiddleDemo
强>
输出:
╔═════════╦════════════╦══════╗
║ Admin ║ Moderator ║ User ║
╠═════════╬════════════╬══════╣
║ Tony ║ (null) ║ Sara ║
║ (null) ║ (null) ║ John ║
╚═════════╩════════════╩══════╝