Question

当我以JSON格式从Request body传递参数时，不会遇到web api。我的代码：

    public async Task<HttpResponseMessage> Upload([FromBody]AddPhotoBizPrm addPhotoBizPrm)
    {
        json_obj.RESPONSE = new { };
        string images = "";
        if (Request.Content.IsMimeMultipartContent())
        {

            var provider = new MultipartMemoryStreamProvider();
            await Request.Content.ReadAsMultipartAsync(provider);
            foreach (var file in provider.Contents)
            {
                var filename = file.Headers.ContentDisposition.FileName.Trim('\"');
                var buffer = file.ReadAsByteArrayAsync();
                images += filename;
                //Do whatever you want with filename and its binary data.
            }
        }
        json_obj.RESPONSE = images;
        json_obj.MESSAGE = "";
        json_obj.STATUS_CODE = 701;
        return new HttpResponseMessage()
        {
            Content = new StringContent("ok")
        };
    }

我从请求正文传递参数：

{
deviceid:"",
rate:2,
review:"",
skuid:123,
userId:875904
}

Answer 1

解决了这个问题。我使用的是content-type = multipart / form-data，因此我们无法将json参数传递给请求体。所以我们将像数据一样传递参数设备ID =＆＃34;＆＃34;＆安培;率= 2及复习=＆＃34;＆＃34;＆安培; skuid = 123＆安培;用户id = 875904

如何通过Web API使用Content-Type请求body参数访问：multipart / form-data？

1 个答案: