Question

我使用以下代码发布带有multipart/form-data内容类型的请求，但获得例外：

远程服务器返回错误：（532）。

我如何解决这个问题？

public void request222(string cgid)
{
    NameValueCollection nvc = new NameValueCollection();
    nvc.Add("action:WebManager", "OK");
    nvc.Add("cg_id", "" + cgid + "");

    var boundary = "---------------------------DateTime.Now.Ticks.ToString("x")";

    //creating request
    var wr = (HttpWebRequest)WebRequest.Create("http://189.126.121.79:8093/API/CCG");
    wr.ContentType = "multipart/form-data; boundary=" + boundary;
    wr.Method = "POST";
    wr.KeepAlive = true;

    //sending request
    using (var requestStream = wr.GetRequestStream())
    {
        using (var requestWriter = new StreamWriter(requestStream, Encoding.UTF8))
        {
            //params
            const string formdataTemplate = "Content-Disposition: form-data; name=\"{0}\"\r\n\r\n{1}";
            foreach (string key in nvc.Keys)
            {
                requestWriter.Write(boundary);

                requestWriter.Write(String.Format(formdataTemplate, key, nvc[key]));
            }
            requestWriter.Write("\r\n--" + boundary + "--\r\n");
        }
    }

    //reading response
    try
    {

        using (var wresp = (HttpWebResponse)wr.GetResponse())
        {
            if (wresp.StatusCode == HttpStatusCode.OK)
            {
                using (var responseStream = wresp.GetResponseStream())
                {
                    if (responseStream == null)

                    using (var responseReader = new StreamReader(responseStream))
                    {
                        string s= responseReader.ReadToEnd();
                    }
                }
            }

            throw new ApplicationException("Error Server status code: " + wresp.StatusCode.ToString());
        }
    }
    catch (Exception ex)
    {
        throw new ApplicationException("Error while uploading file", ex);
    }
}

Answer 1

而不是自己实现它，请考虑使用新的API：HttpClient类。它为multipart/form-data support。

有关实际示例，请参阅例如this answer on another question

此外，最好只使用application/x-www-form-urlencoded，因为您的请求中没有发布任何文件（至少在您提供的示例中）

multipart / form-data内容类型请求

1 个答案: