Question

我想这样做：有一个名为＆＃39; Main＆＃39;的课程。还有另一个名为“aClass＆＃39;”的课程。还有一个名为“线程”的课程。这是我们的线程类。＆＃39;主＆＃39;是我们的主类，我们从Main类开始我们的Thread类。当我们的Thread类启动时，它会从run（）函数发出一个信号...... ＆＃39;主＆＃39;和＆＃39; aClass＆＃39;课程试图捕捉这些信号。＆＃39;主＆＃39; class能够捕获从Thread类发出的信号但是＆＃39; aClass＆＃39;因为我没有从'aClass＆＃39;开始QThread，所以无法捕获相同的信号。我只在＆＃39; aClass＆＃39;。

中定义了它

以下是代码：

#!/usr/bin/env python

from PyQt4.QtGui import *
from PyQt4.QtCore import *
import sys


class Main(QMainWindow):
    def __init__(self):
        QMainWindow.__init__(self)

        self.setWindowTitle("Test")
        self.aClass = aClass()

        self.thread = Thread()
        self.thread.printMessage.connect(self.write)
        self.initUI()

    def initUI(self):
        self.button = QPushButton("Start Process", self)
        self.button.clicked.connect(self.startProcess)

    def startProcess(self):
        self.thread.start()

    def terminateProcess(self):
        self.thread.terminate()

    def write(self):
        print "Main: hello world..."


class aClass(object):
    def __init__(self):
        print "aClass: I have been started..."
        self.thread = Thread()
        self.thread.printMessage.connect(self.write)

    def write(self):
        print "aClass: hello world..."

class Thread(QThread):
    printMessage = pyqtSignal()

    def __init__(self):
        QThread.__init__(self)
        print "Thread: I have been started..."

    def run(self):

        self.printMessage.emit()
        print "Thread: I emitted the message."

if __name__ == "__main__":
    app = QApplication(sys.argv)
    root = Main()
    root.show()
    app.exec_()

结果：程序启动时，输出为：

aClass: I have been started... 
Thread: I have been started...
Thread: I have been started...

当我点击“开始流程”时按钮，输出为：

Thread: I emitted the message.
Main: hello world...

总产量：

aClass: I have been started...
Thread: I have been started...
Thread: I have been started...
Thread: I emitted the message.
Main: hello world...

点击“启动流程＆＃39;

”后我想要获得的输出

Thread: I emitted the message.
Main: hello world...
aClass: hello world...

我想要这个结果，但我不想使用来自＆＃39; aClass＆＃39;的自我.thread.start（）命令。因为我只想运行Thread一次......

Answer 1

您正在做的是在Thread对象中创建第二个aClass，该Thread与Main中的self.thread不同。您需要将Main中的write信号与self.aClass对象中的广告符class Main(QMainWindow): def __init__(self): QMainWindow.__init__(self) self.setWindowTitle("Test") self.aClass = aClass() self.thread = Thread() self.thread.printMessage.connect(self.write) self.thread.printMessage.connect(self.aClass.write) ... class aClass(object): def __init__(self): print "aClass: I have been started..." #self.thread = Thread() #This makes a new Thread #self.thread.printMessage.connect(self.write) def write(self): print "aClass: hello world..." self.initUI()相关联。

你想这样做：

if (element.parentNode == divElement) { ... }

如何从QThread为2个classess发出相同的信号

1 个答案: