我正在尝试转换以下T-SQL Select查询以排除“存在”子句并包含“加入”子句。但我最终没有得到正确的结果。这个专家团队的一些人可以帮我提一些技巧。
select *
FROM HRData
INNER JOIN (
SELECT eeceeid, MIN(eecdateoftermination) eTermDate
FROM dbo.empcomp
INNER JOIN
(
SELECT xeeid FROM HRData_EEList
INNER JOIN dbo.empcomp t ON xeeid = eeceeid AND xcoid = eeccoid
WHERE eecemplstatus = 'T' AND eectermreason <> 'TRO' AND eeccoid <> 'WAON6'
AND EXISTS ( SELECT 1 FROM dbo.empded
INNER JOIN dbo.dedcode on deddedcode = eeddedcode AND deddedtype = 'MED' AND (eedbenstopdate IS NULL OR eedbenstopdate > '12/31/2005')
WHERE eedeeid = xeeid AND eedcoid = xcoid )
GROUP BY xeeid
HAVING COUNT(*) > 1) Term ON xeeid = eeceeid
group by eeceeid
) Terms ON eeid = eeceeid AND Termdate = eTermDate
答案 0 :(得分:0)
有趣的请求。
select *
FROM HRData
INNER JOIN (
SELECT eeceeid, MIN(eecdateoftermination) eTermDate
FROM dbo.empcomp
INNER JOIN
(
SELECT xeeid FROM HRData_EEList
INNER JOIN dbo.empcomp t ON xeeid = eeceeid AND xcoid = eeccoid
INNER JOIN
( SELECT DISTINCT xeeid, xcoid FROM dbo.empded
INNER JOIN dbo.dedcode on deddedcode = eeddedcode AND deddedtype = 'MED' AND (eedbenstopdate IS NULL OR eedbenstopdate > '12/31/2005')
-- WHERE eedeeid = xeeid AND eedcoid = xcoid
) AS A ON xeeid = A.xeeid AND eedcoid = A.eedcoid
WHERE eecemplstatus = 'T' AND eectermreason <> 'TRO' AND eeccoid <> 'WAON6'
GROUP BY xeeid
HAVING COUNT(*) > 1) Term ON xeeid = eeceeid
group by eeceeid
) Terms ON eeid = eeceeid AND Termdate = eTermDate
答案 1 :(得分:0)
将EXISTS
转换为JOIN
的算法非常简单。
而不是
FROM A
WHERE EXISTS (SELECT *
FROM B
WHERE A.Foo = B.Foo)
使用
FROM A
INNER JOIN (SELECT DISTINCT Foo
FROM B) AS B
ON A.Foo = B.Foo
但第一个可能会更好地优化