Question

您能告诉如何使用orderBy来处理具有各种字段类型（字符串和数字）的对象吗？例如

_.orderBy([{a: 3}, {a: 2}, {a: 'a'}, {a: 1}, {a: 'c'}, {a: 'b'}], ['a'], ['asc'])

我有

[{"a":2},{"a":3},{"a":"a"},{"a":1},{"a":"b"},{"a":"c"}]

但我怎么能得到像

这样的东西

[{"a":1},{"a":2},{"a":3},{"a":"a"},{"a":"b"},{"a":"c"}]

Answer 1

比较值的_.toString结果。

var input = [{a: 3}, {a: 2}, {a: 'a'}, {a: 1}, {a: 'c'}, {a: 'b'}],
    output = _.sortBy(input, o => _.toString(o['a']));

console.log(output);

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如果要先根据类型进行分区，请使用_.groupBy然后排序。

var input = [{a: 3}, {a: 2}, {a: 'a'}, {a: 1}, {a: 'c'}, {a: 'b'}];
    
var output = _(input)
    .groupBy(o => typeof o['a'])
    .map(a => _.sortBy(a, 'a'))
    .flatten()
    .value();

console.log(output);

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orderBy具有混合类型的列

1 个答案: