Question

我的日期范围为1-Jul-2016至10-Jul-2016。我想提取该范围内的周数和剩余天数，如

No. of Weeks = 1 

No. of Remaining Days = 3

我知道如何使用

找到日期或星期差异

DATEDIFF(DAY,@ArrivalDate,@DepartureDate)
DATEDIFF(WEEK,@ArrivalDate,@DepartureDate)

但是如何查找并获取日期是否仅包含完整的周数或周和日。

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Answer 1

尝试以下查询

DECLARE @StartDate DATETIME = '2016.07.01'
DECLARE @EndDate DATETIME = '2016.07.10'

SELECT 
    DATEDIFF(DAY, @StartDate, @EndDate) / 7 AS 'No. of Weeks', -- 1
    (DATEDIFF(DAY, @StartDate, @EndDate) % 7) + 1 AS 'No. of Remaining Days' -- 3

Answer 2

DECLARE @StartDate DATETIME = '2016.07.01'
DECLARE @EndDate DATETIME = '2016.07.10'

SELECT 
    -- DATEDIFF(DAY, @StartDate, @EndDate) / 7 AS 'No. of Weeks', -- 1
    DATEDIFF(WEEK, @StartDate, @EndDate) AS 'No. of Weeks',
   (DATEDIFF(DAY, @StartDate, @EndDate) % 7) + 1 AS 'No. of Remaining Days' -- 3

从SQL中的日期范围中提取整周和剩余天数

2 个答案: