我粘贴了SICStus Prolog 4.3.3
SP_define_c_predicate()
样本按原样并且<失败:
$ /usr/local/sicstus4.3.3/bin/splfr square.pl square.c square.c: In function ‘square_it’: square.c:7:3: error: unknown type name ‘SP_WORD’ SP_WORD arg1; ^ square.c:13:3: warning: passing argument 2 of ‘sp_GlobalSICStus_square->dispatch_API_SICSTUS_H->pSP_get_integer’ from incompatible pointer type [enabled by default] if (!SP_get_integer(tmp,&arg1)) ^ square.c:13:3: note: expected ‘SP_integer *’ but argument is of type ‘int *’ Uncaught exception from user code: ! Could not compile square.c
到目前为止,我为SP_WORD
抓取了SICStus C包含文件 - 无济于事。
您是否有一些提示我如何才能使其发挥作用?提前谢谢!
(仅供参考:我使用x86-64 Linux Mint 17和gcc版本4.8.4。)
答案 0 :(得分:3)
示例应该使用SP_integer
而不是内部类型SP_WORD
。