Question

这是我的代码：我在这个方法中遇到错误

public void saying(){
        System.out.println("Your first gf was %s", getName());
    }

.....

无法使用getName（）...因为它要求将返回类型更改为Object []，而返回与Scanner对象输入类型不兼容，因为必须输入String Value .... here String temp = input.nextLine（）;

public class UsingManyMethodsInstances2 {
private String girlName;
public void setName(String temp){
    girlName=temp;
}
public String getName(){
    return girlName;
}
public void saying(){
    System.out.println("Your first gf was %s", getName());
}
}

public class ManyMethodsInstances2 {

public static void main(String args[]){

    Scanner input = new Scanner(System.in);
    UsingManyMethodsInstances2 manyMethodsInstances2Object = new UsingManyMethodsInstances2();
    System.out.println("Enter name of first gf here: ");
    String temp = input.nextLine();
    manyMethodsInstances2Object.setName(temp);
    manyMethodsInstances2Object.saying();
}

}

Answer 1

更改

System.out.println("Your first gf was %s", getName());

到

System.out.printf("Your first gf was %s", getName());

println只接受对象或字符串。

Answer 2

你的问题是System.out.println()只接受一个参数。字符串应该与变量连接。您的saying()方法应该是：

public void saying(){
    System.out.println("Your first gf was " + getName());
}

如果您确实想使用占位符，可以使用System.out.printf()：

public void saying(){
    System.out.printf("Your first gf was %s", getName());
}

或者您也可以在String.format()内使用println()：

public void saying(){
    System.out.println(String.format("Your first gf was {0}", getName()));
}

Answer 3

您错误地使用该方法来打印连接的消息...

你可以这样做：

System.out.printf("Your first gf was %s", getName());

或

System.out.println(String.format("Your first gf was %s", getName()));

但是

`System.out.println("Your first gf was %s", getName());`

不正确，因为该方法需要仅1 参数..

我在说（）方法无法编译时遇到错误？

3 个答案: