Question

我在encodebat上尝试这个小问题列表。这是问题的链接：http://codingbat.com/prob/p108886 我必须计算列表的总和，除了忽略一个以6开头并以7结尾的子列表。我正在分享我写的代码，任何人都可以帮我解决我犯错误的地方。

def sum67(nums):
  def c6(six):
    if len(six) > 0:
      if 6 not in six:
        return six
      else:
        count= 0
        for a in six:
          if a== 6:
            count = count + 1

        for b in range(count):
          in1= six.index(6)
          in2= six.index(7)

          six= six[0:in1]+six[in2+1:]
        return six
    else:
      return 0

  a= c6(nums)
  return sum(nums)

Answer 1

Here I found the error for the list = [6,6,1, 2, 2, 6, 99, 99, 7]

I have written the same code in tests.py and run with some examples.

I also found that sum(nums) needs to be changed to sum(a)

def sum67(nums):
    def c6(six):
        if len(six) > 0:
            if 6 not in six:
                return six
            else:
                count = 0
                for a in six:
                    if a == 6:
                        count = count + 1

                for b in range(count):
                    in1 = six.index(6)
                    in2 = six.index(7)

                    six = six[0:in1] + six[in2 + 1:]
                return six
        else:
            return 0

    a = c6(nums)
    return sum(a)


numbers = [6,6,1, 2, 2, 6, 99, 99, 7]
sum1 = sum67(numbers)




Traceback (most recent call last):
  File "tests.py", line 26, in <module>
    sum1 = sum67(numbers)
  File "tests.py", line 21, in sum67
    a = c6(nums)
  File "tests.py", line 13, in c6
    in1 = six.index(6)
ValueError: 6 is not in list

Let me know if I am wrong.

I tried below code in my console. It's working for me all my inputs.

def sum67(nums):
    def c6(six):
        if len(six) > 0:
            if 6 not in six:
                return six
            else:
                count = 0
                for a in six:
                    if a == 6:
                        count = count + 1
                for b in range(count):
                    if six and six.__contains__(6) and six.__contains__(7):
                        in1 = six.index(6)
                        in2 = six.index(7)
                        six = six[0:in1] + six[in2 + 1:]
                return six
        else:
            return 0
    a = c6(nums)
    return sum(a)


numbers = [6, 6, 1, 2, 2, 6, 99, 99, 7, 1, 2, 6, 1, 2, 7, 1, 2,6,7]
sum1 = sum67(numbers)
print("Sum value = %s" % sum1)
Sum value = 6

But I am getting below error in the URL( http://codingbat.com/prob/p108886）

Line 12: __contains__ is an invalid attribute name because it starts with "_".

所以我不知道这个错误的原因。

Answer 2

您看到的错误消息实际上不是编译器错误。它是index在未找到参数时引发的异常值：

>>> [1,2,3].index(6)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: 6 is not in list

你需要抓住错误并做出适当的回应：

try:
    in1 = six.index(6)
except ValueError:
    # What should you do if there is no 6 in the list?
    # Do it here.

我收到编译错误：6不在列表中

2 个答案: