Question

我有一个生成时间间隔数组的代码。好吧，它运行良好，它得到3分，开始时间，结束和生成数组的时间（分钟）

known_hosts

它会生成这个数组：

  function GeraHorario(inicio,fim,tempoConsulta)
  {
    var consultas = Math.floor(60/tempoConsulta);
    for (var i = 0; i <= consultas; i++) {
      $scope.consultasHora.push(i)
    }
    var agenda = []
    var data = new Date(2016, 0, 1, inicio, 0, 0, 0)
    var horainicial = inicio
    while (data.getDate() == 1) {
      if(data.getHours() < fim)
      {
          var horario = data.toLocaleTimeString('pt-BR');
          data.setMinutes(data.getMinutes()+tempoConsulta);
          //agenda.push(horario.replace(/(.*)\D\d+/, '$1'));
          var d1 = horario.replace(/(.*)\D\d+/, '$1');
          agenda.push(d1.replace(/:/g,''));
      }else{break}
    }
    console.log(agenda)
    return agenda
  }

我需要的是划分值数组，例如从0900到1000。那实际上这是0900 09:00 10:00然而我删除了：我需要的是对这些间隔时间表进行分组，输入9到10,10到11等等。有人可以帮忙吗？

["0900", "0911", "0922", "0933", "0944", "0955", "1000", "1006", "1017", "1028", "1039", "1050", "1100", "1101", "1112", "1123", "1134", "1145", "1156", "1200", "1207", "1218", "1229", "1240", "1251", "1300", "1302", "1313", "1324", "1335", "1346", "1357", "1400", "1408", "1419", "1430", "1441", "1452", "1500", "1503", "1514", "1525", "1536", "1547", "1558", "1600", "1609", "1620", "1631", "1642", "1653", "1700", "1704", "1715", "1726", "1737", "1748", "1759", "1800", "1810", "1821", "1832", "1843", "1854", "1900"]

Answer 1

您可以将原始数组缩减为地图或其他数组。

var result = agenda.reduce(function( map, hourStr ) {
    var hour = hourStr.charAt(0) + hourStr.charAt(1);
    if (!map.hasOwnProperty(hour)) map[hour] = [];
    map[hour].push(hourStr);
    return map;
}, {});

二维数组版本：

var result = agenda.sort().reduce(function( map, hourStr ) {
        var hour = hourStr.charAt(0) + hourStr.charAt(1);
        if (!map.indices.hasOwnProperty(hour)) {
            map.indices[hour] = map.ary.length;
            map.ary.push([]);
        }
        map.ary[map.indices[hour]].push(hourStr);
        return map;     
    }, {
        'indices' : {},
        'ary' : []
    }).ary;

Answer 2

这是一个非字符串方法：

var groups = {};
for(var index in agenda){
  var time = times[index];
  var groupId = Math.floor(parseInt(time) / 100);
  if(!groups[groupId]) groups[groupId] = [];
  groups[groupId].push(time);
}

组时间间隔数组

2 个答案: