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Question

让我挑选一个关于一项小任务的大脑，这项任务花了我几天的时间才弄明白......

我有一个EditText，用户将输入一个String，用于进行维基百科搜索并提供带有结果的ListView。 EditText应该有1秒的限制，并且必须进行过滤才能检查“不合适”的列表。字符串。如果输入在String列表中，搜索将不会通过，除非用户同时触摸屏幕两个角上的2个隐藏视图，否则它将跳过此检查。

这里有一些片段可以帮助您了解我已经拥有的内容......

// a list of inappropriate content
private static String[] INAPPROPRIATE_CONTENT = {
            "test"
        };

// subscription to the touches happening on hidden view #1
Subscription subSecretLeft = RxView.touches(vSecretLeft)
        .filter(motionEvent -> motionEvent.getAction() == MotionEvent.ACTION_DOWN || motionEvent.getAction() == MotionEvent.ACTION_UP)
        .subscribe(motionEvent -> secretLeftClicked = motionEvent.getAction() == MotionEvent.ACTION_DOWN);

// subscription to the touches happening on hidden view #2
RxView.touches(vSecretRight)
        .filter(motionEvent -> motionEvent.getAction() == MotionEvent.ACTION_DOWN || motionEvent.getAction() == MotionEvent.ACTION_UP)
        .subscribe(motionEvent -> secretRightClicked = motionEvent.getAction() == MotionEvent.ACTION_DOWN);

// subscription to the EditText
RxTextView.textChanges(etxtSearchFilter)
        .throttleLast(1, TimeUnit.SECONDS, AndroidSchedulers.mainThread())
        .map(c -> c.toString().trim())
        .filter(s -> !(s.isEmpty() || isInappropriate(s)))
        .subscribe(s -> fetchWikiSearch(s));

WhereInappropriate（String s）是检查数组中是否找到该术语的方法，fetchWikiSearch（String s）执行搜索并填充ListView。

我尝试了几种方法，我可以提出的最后一种方法如下：

Observable.zip(
        Observable.combineLatest(
                RxView.touches(vSecretLeft)
                        .filter(motionEvent -> motionEvent.getAction() == MotionEvent.ACTION_DOWN || motionEvent.getAction() == MotionEvent.ACTION_UP || motionEvent.getAction() == MotionEvent.ACTION_CANCEL),
                RxView.touches(vSecretRight)
                        .filter(motionEvent -> motionEvent.getAction() == MotionEvent.ACTION_DOWN || motionEvent.getAction() == MotionEvent.ACTION_UP || motionEvent.getAction() == MotionEvent.ACTION_CANCEL),
                (ev1, ev2) -> ev1.getAction() == MotionEvent.ACTION_DOWN && ev2.getAction() == MotionEvent.ACTION_DOWN
        ).asObservable(),
        RxTextView.textChanges(etxtSearchFilter)
                .throttleLast(1, TimeUnit.SECONDS, AndroidSchedulers.mainThread())
                .map(c -> c.toString().trim())
                .filter(s -> !s.isEmpty()),
        (overrideFilter, s) ->
                overrideFilter || !isInappropriate(s) ? s : "BLOCKED"
).subscribe(s -> Log.i("ObservableZip", "s: " + s));

但显然，只要我不触及这些观点，它就不会发出任何东西。即使是Observable.combileLatest（）也不是很好用，因为它只有在两个视图都获得MotionEvent.ACTION_DOWN时才会发出......

如果您有任何提示或实际解决方案，请不要犹豫，发表评论。感谢。

Answer 1

那不够吗？

throttleLast

（我也将debounce更改为Observable.combineLatest( RxView.touches(vSecretLeft) .map(motionEvent -> motionEvent.getAction()) .filter(action -> action == MotionEvent.ACTION_DOWN || action == MotionEvent.ACTION_UP || action == MotionEvent.ACTION_CANCEL) .startWith(MotionEvent.ACTION_UP), RxView.touches(vSecretRight) .map(motionEvent -> motionEvent.getAction()) .filter(action -> action == MotionEvent.ACTION_DOWN || action == MotionEvent.ACTION_UP || action == MotionEvent.ACTION_CANCEL) .startWith(MotionEvent.ACTION_UP), RxTextView.textChanges(etxtSearchFilter) .debounce(1, TimeUnit.SECONDS) .map(c -> c.toString().trim()) .filter(s -> !s.isEmpty()), (leftAction, rightAction, entered) -> { boolean overrideFilter = leftAction == MotionEvent.ACTION_DOWN && rightAction == MotionEvent.ACTION_DOWN; return overrideFilter || !isInappropriate(entered) ? entered : "BLOCKED"; }) .subscribe(s -> Log.i("ObservableCombineLatest", "s: " + s));，因为它在某种程度上感觉更好用于此目的）

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Answer 2

您似乎走在正确的轨道上，但您可能希望用startsWith“初始化”隐藏的视图，即

// subscription to the touches happening on hidden view #1
Subscription subSecretLeft = RxView.touches(vSecretLeft)
        .filter(motionEvent -> motionEvent.getAction() == MotionEvent.ACTION_DOWN || motionEvent.getAction() == MotionEvent.ACTION_UP)
        .startsWith(MotionEvent.ACTION_UP)
        .subscribe(motionEvent -> secretLeftClicked = motionEvent.getAction() == MotionEvent.ACTION_DOWN);

RxAndroid：观察EditText，同时观察2个视图上的触摸

2 个答案:

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