我做的是创建了n个孩子,而且父母使用n个管道向他们发送了“start”消息。每个孩子都有一个烟斗。现在我正在努力做的就是把父母寄回给每个孩子的号码。
这是我的代码,直到现在:
UIGestureRecognizer
}
这是输出:
int main()
{
int n=5;
int p[n-1][2];
int i;
for(i=0;i<n;i++){
if(pipe(p[i])>0){
perror("pipe error");
exit(1);
}
}
for(i=0;i<n;i++){
pid_t pid=fork();
if(pid<0){
perror("fork error");
exit(1);
}
if(pid==0){
int j;
for(j=0;j<n;j++){
close(p[j][1]);
}
for(j=0;j<i;j++){
close(p[j][0]);
}
char msg[256];
int h;
read(p[i][0],&h,sizeof(int));
read(p[i][0],msg,h*sizeof(char));
cout<<i<<"_"<<msg<<endl;
close(p[i][0]);//here I would like to send the number i to the parent
for(j=i+1;j<n;j++){
close(p[j][0]);
}
exit(0);
}
}
char ms[256];
strcpy(ms,"start");
int ho=strlen(ms);
for(i=0;i<n;i++){
if(write(p[i][1],&ho,sizeof(int))==-1){
perror("write error");
exit(1);
}
if(write(p[i][1],ms,ho*sizeof(ms))==-1){
perror("write error");
exit(1);
}
close(p[i][1]);
}
for(int j=0;j<n;j++)
close(p[j][0]);//then read the number of each child and print it
while(wait(NULL)>0){};
exit(0);
所以我成功地将消息开始发送给每个孩子。但是我无法弄清楚父母将如何接收孩子们发送的号码。
答案 0 :(得分:0)
您可以执行类似的过程但是这里父级具有管道的读取端,而子级具有写入端。将上面的示例扩展为仅包含一个管道。每个孩子可以有一个多个管道。
int main()
{
int n=5;
int p[n-1][2];
int pw[2]; // pipe child writes into
int i;
for(i=0;i<n;i++){
if(pipe(p[i])>0){
perror("pipe error");
exit(1);
}
}
if(pipe(pw)>0){
perror("pipe error");
exit(1);
}
for(i=0;i<n;i++){
pid_t pid=fork();
if(pid<0){
perror("fork error");
exit(1);
}
if(pid==0){
int j;
for(j=0;j<n;j++){
close(p[j][1]);
}
close(pw[0]);// close read end - child
for(j=0;j<n;j++){
if ( i!= j ) close(p[j][0]);
}
char msg[256];
int h;
read(p[i][0],&h,sizeof(int));
read(p[i][0],msg,h*sizeof(char));
cout<<i<<"_"<<msg<<endl;
close(p[i][0]);//here I would like to send the number i to the parent
write(pw[1],&i,sizeof(int)); // send i
close(pw[1]);
exit(0);
}
}
char ms[256];
strcpy(ms,"start");
int ho=strlen(ms);
int value;
for(i=0;i<n;i++){
if(write(p[i][1],&ho,sizeof(int))==-1){
perror("write error");
exit(1);
}
if(write(p[i][1],ms,ho*sizeof(ms))==-1){
perror("write error");
exit(1);
}
close(p[i][1]);
close(pw[1]); //close write end
if(read(pw[0],&value,sizeof(int))==-1){ // read from child process
perror("write error");
exit(1);
}
cout << " in main "<<value<<endl; // display number
}
for(int j=0;j<n;j++)
close(p[j][0]);//then read the number of each child and print it
while( wait(NULL) > 0 ){;}
exit(0);
}