SFML错误 - isOpen非标准语法;

时间:2016-07-05 17:34:39

标签: c++ syntax sfml

所以我收到了这个错误:game.cpp(15): error C3867: 'sf::Window::isOpen': non-standard syntax; use '&' to create a pointer to member

Game.cpp

#include "Game.h"
#include <SFML/Graphics.hpp>
#include <SFML/Window.hpp>

Game::Game() :
    window(sf::VideoMode(200, 200), "SFML works!"),
    player() 
{ 
    player.setRadius(40.f);
    player.setPosition(100.f, 100.f);
    player.setFillColor(sf::Color::Cyan);
}

void Game::run() {
    while (window.isOpen) {
        processEvents();
        update();
        render();
    }
}

void Game::processEvents()
{
    sf::Event event;
    while (window.pollEvent(event)) {
        if (event.type == sf::Event::Closed)
            window.close();
    }
}

void Game::update() {

}

void Game::render() {
    window.clear();
    window.draw(player);
    window.display();
}

这是我的game.h

#include <SFML/Graphics.hpp>
#include <SFML/Window.hpp>

class Game {
public:                         
    Game();        
    void run();
    sf::RenderWindow window;
    sf::CircleShape  player;
private:        
    void processEvents();        
    void update();        
    void render();
};

我不知道我做错了什么,我通过其他stackoverflow回答相同的错误,但它们都是一般的,他们不帮我修复这个错误,因为它来自SFML库。如果有人知道如何解决它,请帮助我:)

1 个答案:

答案 0 :(得分:2)

这里while (window.isOpen)您正在测试成员函数指针'window.isOpen'不是nullptr。您打算调用函数while (window.isOpen())