Question

我有3个词典：

zosia = {'imie': 'Zosia', 'zadania': 1, 'quizy': 2, 'testy': 5 },

jas = {'imie': 'Jas', 'zadania': 5, 'quizy': 5, 'testy': 5 },

malgosia = {'imie': 'Malgosia', 'zadania': 3, 'quizy': 3, 'testy': 4 }

包含它们的列表：

studenci = [zosia, jas, malgosia]

我需要在studenci列表中包含的所有词典中创建一个平均值（＆＃39; zadania＆＃39;＆＃39; quizy＆＃39; testy＆＃39;）的函数。所以基本上我需要平均studenci。提前谢谢。

Answer 1

只需将值链接起来，然后使用sum()和len()对其进行平均。请注意，您的问题中的词语后面不能有逗号;将它们包装成元组。

from __future__ import division # only use this if you are in python 2.7
from itertools import chain

zosia = {'imie': 'Zosia', 'zadania': 1, 'quizy': 2, 'testy': 5 }
jas = {'imie': 'Jas', 'zadania': 5, 'quizy': 5, 'testy': 5 }
malgosia = {'imie': 'Malgosia', 'zadania': 3, 'quizy': 3, 'testy': 4 }
studenci = [zosia, jas, malgosia]

def get_average(dicts, values_labels): # you need to specify which members of zosia, jas, malgosia, etc. you want to count
    values = list(chain.from_iterable((D[label] for label in values_labels) for D in dicts))
    average = sum(values)/len(values)
    return average

print(get_average(studenci, ('zadania', 'quizy', 'testy')))

# >>> 3

Answer 2

'Returns a list of the "averages" of each dictionary'
def dict_average(*args):
    averages = []
    for arg in args:
        values = arg.values()
        s = 0
        i = 0
        for v in values:
            try:
                s += v
                i += 1
            except TypeError:
                s += 0
        averages.append(s / i)
    return averages

函数平均字典列表中的值

2 个答案: