Question

使用PDO时如何做到这一点？我曾经这样做但不是PDO。我是否将$attack = $query->execute(array..包裹在if statement？

中

最好的方法是什么？关于我的编码技巧的任何建议将不胜感激：）

这是我的代码

if(isset($_POST['submit'])){
    $firstname  = $_POST['firstname'];
    $middlename = $_POST['middlename'];
    $lastname   = $_POST['lastname'];
    $spousename = $_POST['spousename'];
    $bday       = $_POST['bday'];
    .
    .
    .
    .*other $_POST[''] stuffs*

$q = "INSERT into crf(col_fn, col_mn, col_ln, col_sn, col_bday, col_home, col_telno, col_mobno, col_email, col_gender, col_civilstat)
              VALUES(:fn, :mn, :ln, :sn, :bday,  :homeadd, :telno, :mobno, :email, :gender, :civilstat);";

$query = $db->prepare($q);
try{
$attack= $query->execute(array(
    ":fn"       =>  $firstname,
    ":mn"       =>  $middlename,
    ":ln"       =>  $lastname,
    ":sn"       =>  $spousename,
    ":bday"     =>  $bday,
    ":homeadd"  =>  $homeadd,
    ":telno"    =>  $telno,
    ":mobno"    =>  $mobno,
    ":email"    =>  $emailadd,
    ":gender"   =>  $gender,
    ":civilstat"=>  $civilstat
    ));

}catch(PDOException $e){
    $e->getMessage();
}

?>

Answer 1

http://php.net/manual/en/pdo.query.php

返回值

PDO :: query（）返回PDOStatement对象，或者失败时返回FALSE。

因此，在if == false中包装将非常适合检查查询是否已执行

Answer 2

你不需要它。每个陈述都是成功的，没有引起任何错误。因此，您不需要专门的条件来测试成功。

if(isset($_POST['submit'])){
    unset($_POST['submit'])); // get rid of extra stuff in $_POST
    $q = "INSERT into crf(col_fn, col_mn, col_ln, col_sn, col_bday, col_home, col_telno, col_mobno, col_email, col_gender, col_civilstat)
              VALUES(:firstname, :middlename, :lastname, :spousename, :bday,  :homeadd, :telno, :mobno, :email, :gender, :civilstat);";
    $db->prepare($q)->execute($_POST);
    echo "Success!"; // or whatever. 
}

这是您需要的所有代码

如果成功插入数据库，则创建成功消息

2 个答案: