Question

我正在调用register api，但是当我在模拟器中运行它时显示成功，但数据不会插入数据库中。请建议我做什么完美，以及我如何从服务器端获得响应......请给我这个想法。

这是我的代码：

   @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        name = (EditText)findViewById(R.id.e_username);
        email = (EditText)findViewById(R.id.e_email);
        password = (EditText)findViewById(R.id.e_password);
        register = (Button)findViewById(R.id.btn) ;

        register.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                GetCheckEditTextIsEmptyOrNot();

                if (CheckEditText) {

                    SendDataToServer(Getname, GetEmail, GetPassword);

                } else {

                    Toast.makeText(MainActivity.this, "Please fill all form fields.", Toast.LENGTH_LONG).show();

                }
            }
        });

    }
    public void GetCheckEditTextIsEmptyOrNot(){

        Getname = name.getText().toString();
        GetEmail = email.getText().toString();
        GetPassword = password.getText().toString();

        if(TextUtils.isEmpty(Getname) || TextUtils.isEmpty(GetEmail) || TextUtils.isEmpty(GetPassword))
        {

            CheckEditText = false;

        }
        else {

            CheckEditText = true ;
        }

    }
    public void SendDataToServer(final String patient_firstname, final String patient_email, final String patient_password){
        class SendPostReqAsyncTask extends AsyncTask<String, Void, String> {
            @Override
            protected String doInBackground(String... params) {

                String QuickName = patient_firstname ;
                String QuickEmail = patient_email ;
                String QuickPassword = patient_password;

                List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();

                nameValuePairs.add(new BasicNameValuePair("name", QuickName));
                nameValuePairs.add(new BasicNameValuePair("email", QuickEmail));
                nameValuePairs.add(new BasicNameValuePair("password", QuickPassword));

                try {
                    HttpClient httpClient = new DefaultHttpClient();

                    HttpPost httpPost = new HttpPost(DataParseUrl);

                    httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

                    HttpResponse response = httpClient.execute(httpPost);
                  //  Log.d("reponse","error : "+d.toString);

                    HttpEntity entity = response.getEntity();


                } catch (ClientProtocolException e) {
                    Log.e("log_tag","error : "+e.toString());
                } catch (IOException e) {
                    Log.e("log_tag","error : "+e.toString());
                }
                // return "Data Submit Successfully";

                try {
                    BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
                    StringBuilder sb = new StringBuilder();
                    String line = null;
                    while ((line = reader.readLine()) != null) {
                        sb.append(line + "\n");
                    }
                    is.close();
                    json = sb.toString();
                    Log.d("JSON String",json);
                } catch (Exception e) {
                    Log.e("Buffer Error", "Error converting result " + e.toString());
                }
                return "Data Submit Successfully";
            }

            @Override
            protected void onPostExecute(String result) {
                super.onPostExecute(result);

                Toast.makeText(MainActivity.this, "Data Submit Successfully", Toast.LENGTH_LONG).show();

            }
        }
        SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
        sendPostReqAsyncTask.execute(patient_firstname, patient_email, patient_password);
    }
}

我也没有在logcat中收到任何错误。

Answer 1

它像你一样使用post执行消息它总是会在后台执行完毕后显示。无论什么是背景中的代码。首先你看到你的api是正确使用任何brouser命中api所有参数如果数据存储响应任何json catch jsone和parsh json数据和消息当json发送成功按摩

数据未插入数据库但在模拟器中获取成功消息

1 个答案: