我正在尝试将表单结果放入数据库但它无法正常工作。似乎没有错误发生，我的代码出了什么问题？ 这是我的第一页预订表格：
$booking_sql = "SELECT * FROM calendar, missions WHERE calendar_id = '%d' AND calendar.missions_id = missions.missions_id" ;
$_SESSION['booking']['calendar'];
$booking_query = mysqli_query($dbconn, $booking_sql) or die(mysqli_error());
$rsBooking = mysqli_fetch_assoc($booking_query);
?>
<form action="confirm.php" method="post" name="fmNumCon" id="fmNumCon">
<div class="row"><span class="label"><strong class="full"></strong></span> <span class="element"><h4><?php echo $rsBooking['missions_name'].', '.$rsBooking['calendar_date']; ?></h4></span></div>
<div class="row"><span class="label"><h4>*Number of people:</h4></span><span class="element">
<select name="number" id="number" onchange="getNumber()">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
</span></div>
<!-- <div class="row"><span class="label"</span><span class="element"><h4>$NZDisplay cost per person.00</h4><input type="hidden" name="price" id ="price" value="" /></span></div>
<div class="row"><span class="label"> </span><span class="element">
<a id="update" href="booking.php?mode=update">Update cost</a>
</span></div> -->
<div class="row"><strong class="full"><h4>Conatact details:</h4></strong> </div>
<div class="row">
<input name="name" type="text" id="name" value="<?= isset($name) ? $name : ''?>" placeholder="name"/>
</div>
<div class="row">
<input name="$phone" type="text" id="phone" placeholder="phone" value="<?= isset($phone) ? $phone : ''?>"/>
</div>
<div class="row">
<input name="email" type="text" id="email" placeholder="email" value="<?= isset($email) ? $email : ''?>"/>
</div>
<div class="row">
<input type="reset" name="Reset" value="Reset" />
<input type="submit" name="Submit" value="Continue" />
</div>
</form>
以下是确认页面：
$number = $_SESSION['booking']['number'];
$phone = $_POST['phone'];
$email = $_POST['email'];
require_once('includes/dbconn.php');
$booking_sql = sprintf("SELECT * FROM calendar, missions WHERE calendar_id = '%d' AND calendar.missions_id = missions.missions_id", $_SESSION['booking']['calendar']);
$booking_query = mysqli_query($dbconn, $booking_sql) or die(mysqli_error());
$rsBooking = mysqli_fetch_assoc($booking_query);
?>
<form action="thanks.php" method="post" name="fmConfirm" id="fmConfirm" display="hidden">
<div class="row"><?php echo $rsBooking['missions_name']; ?></div>
<div class="row"><input type="hidden" name="number" value ="<?php echo $number?>"></input></div>
<div class="row"><input type="hidden" name="name" value ="<?php echo $name?>"></input></div>
<div class="row"><input type="hidden" name="phone" value ="<?php echo $phone?>"></input></div>
<div class="row"><input type="hidden" name="email" value ="<?php echo $email?>"></input></div>
<div class="row"><span class="label"> </span> <span class="element"><a href="booking.php?calendar_id=<?php echo $_SESSION['booking']['calendar']; ?>&number=<?php echo $_SESSION['booking']['number']; if (!$_COOKIE['PHPSESSID']) { echo '&'.SID; } ?>">Edit details</a></span></div>
<div class="row"><span class="label"> </span><span class="element">
<input type="submit" name="Submit" value="Finsih" />
</span></div>
</form>
这是我的感谢页面：
<?php require_once('includes/dbconn.php'); ?>
<?php session_start();
$date = date('Y-m-d');
// $calendar = $_POST['calendar_date'];
$name = $_POST['name'];
$number = $_POST['number'];
$phone = $_POST['phone'];
$email = $_POST['email'];
// $booking_sql = "INSERT into bookings (calendar_id, booking_name,
// booking_number, booking_phone,
// booking_email, booking_date) VALUES ('$calendar','$name', 'number', 'phone', 'email')";
$booking_sql = "INSERT INTO bookings (booking_name,
booking_number, booking_phone,
booking_email, booking_date)
VALUES ('$name','$number','$phone','$date')";
$dbconn->query($booking_sql);
// $sql = "INSERT INTO bookings (booking_fname, booking_lname, booking_email, user_id, date_id)
// VALUES ('$fName','$lName','$email', '$userid', '$dateid')";
// $dbc->query($sql);
$booking_query = mysqli_query($dbconn, $booking_sql);
$_SESSION = array();
// session_destroy();
// if(!isset($_COOKIE['active'])) {
// setcookie('active', 'no', time() + 31536000);
// }
?>
<h2>Booking complete </h2>
<p> </p>
<p>Thank you for choosing <strong>Mountain Bike Missions</strong>.</p>
<p>To check your booking immediately, you can log in with your email address <a href="login.php">here</a>. At any another time, please use the <strong>Check booking</strong> link in the <strong>Booking</strong> section of the site.</p>
答案 0 :(得分：1)
我稍微调整了你的thanks.php。
在您使用mysqli的过程语法的其他脚本中，在thanks.php中，您切换到了对象语法
删除了所有这些注释行
session_start（）应该始终位于程序之上（在ini-directives之后），如果你在一个包含文件中有一些意外输出它会导致致命错误，否则
我使用准备好的状态来处理从用户那里获得的数据，这样，如果输入中有特殊字符，则不能破坏查询的格式
启用了display_errors，以便显示您的错误（当您完成测试后，您可以删除这些行，您不希望在高效时向用户显示技术错误消息）
使用trigger_error来捕获数据库抛出的错误，将它们视为php错误
代码如下所示：
<?php
/*
* enable display_errors
*/
ini_set('display_errors', 1);
error_reporting(-1);
/*
* start session, construct connection to db
*/
session_start();
require_once('includes/dbconn.php');
/*
* define your variables
*/
$date = date('Y-m-d');
$name = $_POST['name'];
$number = $_POST['number'];
$phone = $_POST['phone'];
$email = $_POST['email'];
/*
* define your sql-statemnt
* send the statement to the database "preparation"-process
* check if the database had any troubles by asking it for errors
*/
$booking_sql = "INSERT INTO bookings (booking_name, booking_number, booking_phone, booking_email, booking_date) VALUES (?, ?, ?, ?, ?)";
$stmt = mysqli_prepare($dbconn ,$booking_sql);
if(mysqli_errno($dbconn) !== 0){
trigger_error(mysqli_error($dbconn));
}
/*
* bind your variables to the prepared statement
* execute the statement
* again, ask if the database had any troubles
*/
mysqli_stmt_bind_param($stmt, "sssss", $name, $number, $phone, $email, $date);
mysqli_stmt_execute($stmt);
if(mysqli_errno($dbconn) !== 0){
trigger_error(mysqli_error($dbconn));
}
$_SESSION = array();
?>
<h2>Booking complete </h2>