Question

我正在编写我的第一个小型Access 2003应用程序。我有两个问题，我无法弄清楚如何结合。我想要的是获取日期范围内的所有路线编号，计算日期范围内每条路线的总行数，并计算延迟的数量。我有这两个查询让我在那里的一部分，只是无法弄清楚如何在Access查询中组合它们。

PARAMETERS StartDate DateTime, EndDate DateTime;
SELECT [ROUTE #], Count(*) AS Total
FROM [On time performace audits] 
WHERE ((([On time performace audits].DATE) Between [StartDate] And [EndDate]))
GROUP BY [Route #];

PARAMETERS StartDate DateTime, EndDate DateTime;
SELECT [Route #], Count(*) as Late
FROM [On time performace audits]
WHERE ([On time performace audits].DATE Between [StartDate] And [EndDate]) AND (    Minute( [ACTUAL TIME]- [SCHEDULED TIME]) >=6)
GROUP BY [Route #];

我不是一个SQL人，更像是一个LINQ人，在习惯VS2010后在Access 2003中编写一个快速而又脏的应用程序有点痛苦。无论如何，希望你能帮忙。感谢。

Answer 1

在第二个示例查询中，您确定要使用Minute（）函数吗？

如果您希望持续2个日期/时间值，请使用DateDiff（）函数。

Debug.Print DateDiff("n", #2010/09/27 01:00#, #2010/09/27 02:10#)
70

Debug.Print Minute(#2010/09/27 02:10# - #2010/09/27 01:00#)
10

如果你想要DateDiff（）方法，试试这个：

PARAMETERS StartDate DateTime, EndDate DateTime;
SELECT t.[ROUTE #], t.Total, l.Late
FROM
    (SELECT [ROUTE #], Count(*) AS Total
    FROM [On time performace audits]
    WHERE ((([DATE]) Between [StartDate] And [EndDate]))
    GROUP BY [ROUTE #]) AS t
    LEFT JOIN (
        SELECT [ROUTE #], Count(*) AS Late
        FROM [On time performace audits]
        WHERE ((([DATE]) Between [StartDate] And [EndDate]))
            And DateDiff("n",[SCHEDULED TIME],[ACTUAL TIME]) >= 6
        GROUP BY [ROUTE #]
        ) AS l
    ON t.[ROUTE #] = l.[ROUTE #];

注意我在DATE字段名称后面加上方括号，以区别于VBA Date（）函数。

Answer 2

您还可以使用UNION [ALL]查询将结果集合并为一个...

Answer 3

问题是如何组合这两个查询。 UNION ALL将是IMO的最佳方式，如下所示：

PARAMETERS StartDate DateTime, EndDate DateTime;
SELECT 'All' As Type, [ROUTE #], Count(*) AS Total
FROM [On time performace audits]  
WHERE DATE Between StartDate And EndDate
GROUP BY [Route #]
UNION ALL
SELECT 'Late', [Route #], Count(*)
FROM [On time performace audits] 
WHERE DATE Between StartDate And [EndDate AND 
(Minute( [ACTUAL TIME]- [SCHEDULED TIME]) >=6) 
GROUP BY [Route #];

Access 2003：如何组合两个计数查询

3 个答案: