Question

我正在尝试将这两个SQL查询结合起来，以显示访问列中具有最高计数1的用户名，其中itemID为2且访问权限为1。

我如何将这两个语句组合起来产生这个结果？

显示具有最高权限的帐户：

SELECT UserName, COUNT(Access) AS Count 
FROM Permissions
GROUP BY UserName, Access
HAVING Access = 1
ORDER BY Count DESC

Result:
Username    AccessCount
user1       2
user2       1
user3       2

显示具有Data Manager访问权限的所有帐户：

SELECT UserName FROM Permissions
where itemid = 2 AND Access = 1

Result:
Username
user1
user2

权限表示例数据：

itemID  UserName    Access
1       user1       1
2       user1       1
3       user1       1
1       user2       0
2       user2       1
3       user2       0
1       user3       1
2       user3       0
3       user3       1

结果将是user1，因为他们可以访问itemID 2并获得最高访问权限。

Answer 1

SQLFiddle demo here

SELECT TOP 1 UserName, COUNT(Access) AS Count 
FROM Permissions ps
WHERE Access = 1
AND
userNAme in 
     (SELECT UserName 
        FROM Permissions
         where itemid = 2 
           AND Access = 1
      )
GROUP BY UserName
ORDER BY Count DESC

Answer 2

SELECT TOP 1 *
FROM 
(
SELECT [USERNAME] as un,COUNT(ACCESS) AS COUNT
FROM Permissions    
GROUP BY USERNAME,ACCESS
HAVING ACCESS=1     
) a
WHERE EXISTS (SELECT [USERNAME] FROM Permissions WHERE [USERNAME]=a.un and itemid=2)
ORDER BY COUNT DESC

结合两个SQL查询 - COUNT和WHERE

2 个答案: