Question

我们假设我有一个开始日期2016-06-19 09:30:00和一个结束日期2016-06-19 10:20:00

我想获得在开始下一个小时之前或者在按小时和日期分组的最后时间之前每小时经过的时间，我想要实现的结果（没有任何成功）将是像这样的东西：

hour |    date    | time_elapsed_in_seconds
 9   | 2016-06-19 |  1800 (there are 1800 seconds between 09:30:00 and 10:00:00)
 10  | 2016-06-19 |  1200 (there are 1200 seconds between 10:00:00 and 10:20:00)

Answer 1

试试这个：

        with table1 as (
      select '2016-06-19 09:30:00'::timestamp without time zone start_date,'2016-06-19 10:20:00'::timestamp without time zone end_date
      )


    select extract(hour from the_hour) "hour",the_hour::date "date",extract (epoch from (new_end-new_start)) "time_elapsed" from (
        select the_hour,CASE WHEN date_trunc('hour',start_date)=the_hour then start_date else the_hour end new_start,
                    CASE WHEN date_trunc('hour',end_date)=the_hour then end_date else the_hour+'1 hour'::interval end new_end 
           from (
              select generate_series(date_trunc('hour',start_date),end_date,'1 hour'::interval) the_hour,start_date,end_date from table1 
            ) a 
         ) b

两个日期之间按小时分组的秒数

1 个答案: